我正在为 iOS 制作一个应用程序。该应用程序必须显示来自 MYSQL 数据库的结果,并且我在应用程序和数据库之间有一个 API。数据库发送有效的 JSON(这是在我的浏览器中):
[{"naam":"Maurice","id":2},{"naam":"Klaas","id":6},{"naam":"Mariska","id":8}]
但我在我的申请中看不到一个以上的结果。我搜索例如“M”,它只返回第一个莫里斯。我希望该应用程序也显示 Mariska。
谁能解释我如何在我的 iOS 应用程序中显示多个结果?
提前致谢,
莫里斯。
这里有更多代码:
ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];
[request setPostValue:@"1" forKey:@"rw_app_id"];
[request setPostValue:voornaam forKey:@"voornaam"];
[request setPostValue:deviceUniqueIdentifier forKey:@"device_id"];
[request setPostValue:@"1" forKey:@"test"];
[request setDelegate:self];
[request startAsynchronous];
// Hide keyword
[textField resignFirstResponder];
// Clear text field
textView.text = @"";
// Start hud
MBProgressHUD *hud = [MBProgressHUD showHUDAddedTo:self.view animated:YES];
hud.labelText = @"Zoeken...";
return TRUE;
}
- (void)requestFinished:(ASIHTTPRequest *)request
{
[MBProgressHUD hideHUDForView:self.view animated:YES];
if (request.responseStatusCode == 400) {
textView.text = @"Invalid code";
}
else if (request.responseStatusCode == 403) {
textView.text = @"Code already used";
}
else if (request.responseStatusCode == 204) {
textView.text = @"No content";
}
else if (request.responseStatusCode == 412) {
textView.text = @"Precondition Failed";
}
else if (request.responseStatusCode == 200) {
NSString *responseString = [request responseString];
NSDictionary *responseDict = [responseString JSONValue];
NSString *naam = [responseDict objectForKey:@"naam"];
// if ([unlockCode compare:@"com.razeware.test.unlock.cake"] == NSOrderedSame) {
textView.text = [NSString stringWithFormat:@"Resultaten: %@", naam];
// } else {
// textView.text = [NSString stringWithFormat:@"Resultaat: %@", unlockCode];
// }
}
else {
textView.text = @"Unexpected error API ERROR";
}
}
- (void)requestFailed:(ASIHTTPRequest *)request
{
[MBProgressHUD hideHUDForView:self.view animated:YES];
NSError *error = [request error];
textView.text = error.localizedDescription;
}
@end
`