我已经为此烦恼了很长时间，我真的希望有人知道这个问题并找到解决它的方法..
我正在生成一个书签，它完美地工作，如果我在 MYSQL 和 PHP 上磨蹭了这么多天之后可以这么说的话。
例如，请考虑生成此书签。
javascript:(function(){ a=document.createElement('script'); a.setAttribute('src','//ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js'); document.body.appendChild(a); data='[["#txtapplicantlname","agrawal","text"],["#txtapplicantfname","aayush","text"],["#txtfather","Ranjan","text"],["#txtmother","Neelam","text"],["#txtPincode","452010","text"],["#txtPhone","2147483647","text"],["#txtEmail","aayush@mail.com","text"],["#rdosex_0,#rdosex_1","1","radio"]]'; for(a=$.parseJSON(data),b=a.length-1;0<=b;b--){ c=a[b]; if (c[2] =='text') { $(c[0]).val(c[1]); } else if (c[2] == 'radio'){ rdata = c[0].split(','); rnum = c[1] - 1; select = rdata[rnum]; $(select).attr('checked', true); } } })();
这是一个封闭编译的小书签的再创作，我无法找到原件，因为它从未被保存（长篇故事......）所以我想我不妨编辑封闭编译的一个。JSON 文件是这样插入的，因为小书签必须动态生成，并且注定要在 HTTPS 网站上运行，因此无法发送 AJAX 调用。
无论如何，代码运行良好，但是当我尝试将其作为超链接插入时，它会中断。如果需要，代码几乎是这样的
"<a href=" + (Code that was shown above) + "> Drag me to your bookmarks bar!</a>"
它坏了。如果需要，这是打印出来的源代码。
<span class='span6'>Please drag the following button to your bookmarks bar! <br>javascript:(function(){ a=document.createElement('script'); a.setAttribute('src','//ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js'); document.body.appendChild(a); data='[["#txtapplicantlname","agrawal","text"],["#txtapplicantfname","aayush","text"],["#txtfather","Ranjan","text"],["#txtmother","Neelam","text"],["#txtPincode","452010","text"],["#txtPhone","2147483647","text"],["#txtEmail","aayush@mail.com","text"],["#rdosex_0,#rdosex_1","1","radio"]]'; for(a=$.parseJSON(data),b=a.length-1;0<=b;b--){ c=a[b]; if (c[2] =='text') { $(c[0]).val(c[1]); } else if (c[2] == 'radio'){ rdata = c[0].split(','); rnum = c[1] - 1; select = rdata[rnum]; $(select).attr('checked', true); } } })();<a href='javascript:(function(){ a=document.createElement('script'); a.setAttribute('src','//ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js'); document.body.appendChild(a); data='[["#txtapplicantlname","agrawal","text"],["#txtapplicantfname","aayush","text"],["#txtfather","Ranjan","text"],["#txtmother","Neelam","text"],["#txtPincode","452010","text"],["#txtPhone","2147483647","text"],["#txtEmail","aayush@mail.com","text"],["#rdosex_0,#rdosex_1","1","radio"]]'; for(a=$.parseJSON(data),b=a.length-1;0<=b;b--){ c=a[b]; if (c[2] =='text') { $(c[0]).val(c[1]); } else if (c[2] == 'radio'){ rdata = c[0].split(','); rnum = c[1] - 1; select = rdata[rnum]; $(select).attr('checked', true); } } })();'>Drag me!</a></span>
它在很多层面上都崩溃了，我已经尝试过很多次来绕过它，但每次我做一个小的改变它都会再次崩溃。我真的希望有一个更可靠的解决方案，如果有人可以帮助我，我将非常感谢..
编辑：这是用 htmlspecialchars 转义双引号后发生的事情
<span class='span6'>Please drag the following button to your bookmarks bar! <br>javascript:(function(){ a=document.createElement('script'); a.setAttribute('src','//ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js'); document.body.appendChild(a); data='[["#txtapplicantlname","agrawal","text"],["#txtapplicantfname","aayush","text"],["#txtfather","Ranjan","text"],["#txtmother","Neelam","text"],["#txtPincode","452010","text"],["#txtPhone","2147483647","text"],["#txtEmail","aayush@mail.com","text"],["#rdosex_0,#rdosex_1","1","radio"]]'; for(a=$.parseJSON(data),b=a.length-1;0<=b;b--){ c=a[b]; if (c[2] =='text') { $(c[0]).val(c[1]); } else if (c[2] == 'radio'){ rdata = c[0].split(','); rnum = c[1] - 1; select = rdata[rnum]; $(select).attr('checked', true); } } })();<a href='javascript:(function(){ a=document.createElement('script'); a.setAttribute('src','//ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js'); document.body.appendChild(a); data='[["#txtapplicantlname","agrawal","text"],["#txtapplicantfname","aayush","text"],["#txtfather","Ranjan","text"],["#txtmother","Neelam","text"],["#txtPincode","452010","text"],["#txtPhone","2147483647","text"],["#txtEmail","aayush@mail.com","text"],["#rdosex_0,#rdosex_1","1","radio"]]'; for(a=$.parseJSON(data),b=a.length-1;0<=b;b--){ c=a[b]; if (c[2] =='text') { $(c[0]).val(c[1]); } else if (c[2] == 'radio'){ rdata = c[0].split(','); rnum = c[1] - 1; select = rdata[rnum]; $(select).attr('checked', true); } } })();'>Drag me!</a></span>