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我有 Procedural,它接受两个 String 参数并从数据库 Oracle 10g 返回 Integer 值。

当尝试打印结果时,我得到 Invalid column index 。

代码是

  try {


             Dbconnection NewConnect = new Dbconnection();
             Connection con = NewConnect.MakeConnect();

            CallableStatement stmt1 = ((Connection) con).prepareCall("{ call login (?, ?, ?)}");
            stmt1.registerOutParameter(1, Types.INTEGER);
            stmt1.setString(2, "ahmed");
            stmt1.setString(3, "ahmed");

             ResultSet rslt = stmt1.executeQuery();

             if (rslt.next())
             {

                 System.out.println( rslt.getInt(1)); 
             }

程序登录

   create or replace 
    PROCEDURE login

        (p_username  teacher.username%TYPE,
                    p_password  teacher.password%TYPE)


    IS
           v_teacher_id   teacher.teacher_id%TYPE;
                      v_username    teacher.username%TYPE ;
           v_password     teacher.password%TYPE ;


    BEGIN
SELECT   teacher_id, username , password
INTO    v_teacher_id , v_username , v_password
FROM    teacher

 where username = p_username and password =p_password  ;

            DBMS_OUTPUT.PUT_LINE (v_teacher_id);



     end login ;
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1 回答 1

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不错的尝试,但这里存在一些错误.... 这样做...您的输出将 100% 确定。

CREATE OR REPLACE PROCEDURE login

(           v_teacher_id OUT teacher.teacher_id%TYPE,
                    p_username  IN teacher.username%TYPE,
                    p_password  IN teacher.password%TYPE)
    IS ..... (blah blah blah)

告诉我一件事,如果您在程序开始时没有提供任何输出参数,您如何期望 Java 代码中的输出?

现在试试,你会从java代码中得到你的输出

 rslt.getInt(1)

一切顺利:)... Surajit

于 2015-07-24T07:49:42.380 回答