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我有一个扫描文本文件并将其放入 CSV 文件的脚本。它抓取debtor信息，然后将creditor信息放在后面。

问题是，它获取了每个，debtor但随后creditor为每个放置了相同的信息debtor，它没有在下面获取新信息debtor：

FasterCSV.open('data.csv', 'a') do |csv|

  debtor_info = results.scan(/^(\d{2}\-\d{5})(\s+)(.*)(\s+)(Total:)(\s+)(\$(\d+\,?   \.?)+)/)

   debtor_info.each do |line|
   case_number = line.at(0)
   debtor = line.at(2).strip
   total_amount = line.at(6)
   csv << [case_number, debtor, total_amount]

    creditor_info = results.scan(/((\d{1,2})\/(\d{1,2})\/(\d{1,4}))\s+(\$(\d+\,?\.?)+)\s+(\d{1,5}BK)\s+(.*)/)

 creditor_info.each do |info|
       date = info.at(0)
       amount = info.at(4)
       fund_number = info.at(6)
       creditor = info.at(7)
       empty = " "
       csv << [empty, date, amount, fund_number, creditor]  

   end
 end
end

这是一些示例输入：

00-000##     Company Inc                            Total: $3,134.55

  2/25/2003       $416.02    0000BK       A Comp Inc
  2/25/2003       $105.60    0000BK       California Imprinted Apparel

  2/25/2003        $58.41    0000BK       John Doe

  2/25/2003        $33.41    0000BK       E Doe & Assoc
  2/25/2003        $78.28    0000BK       Candle Candles

  2/25/2003        $44.74    0000BK       Personnel Svcs
  2/25/2003        $28.34    0000BK       Jane Doe

  2/25/2003        $32.77    0000BK       Water Co

  2/25/2003       $141.21    0000BK       XYX
  2/25/2003       $250.96    0000BK       PDQ INC

  2/25/2003       $146.17    0000BK       RS FM
  2/25/2003       $722.91    0000BK       A Corp

  2/25/2003       $841.14    0000BK       BAC Corp
  2/25/2003       $202.57    0000BK       ABC Communications

  2/25/2003        $32.02    0000BK       YXY SA Corp

00-00128     May June                                           Total: $29.60
  6/26/2002        $29.60    0000BK       May June

00-00653     Joe Doey                                             Total: $347.10

  7/10/2002        $59.62    0000BK       Financial Corp
  7/10/2002       $287.48    0000BK       ABC Corp

00-00657     Thomas P Public                                        Total: $1,096.75
   7/2/2003     $1,096.75    0000BK       Contract Svc

00-00735     Jean Jane                                            Total: $29.89

  6/18/2003        $29.89    0000BK       Jean Jane
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1 回答 1

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使用给定的结构，您需要将债权人或债务人行扫描到一个列表中，然后通过它，在遇到“当前债务人”时设置一个“当前债务人”。

假设results实际上只是您输入文件的一小部分（您没有说，但看起来很可能）：

combined_info = results.scan(/^(\d{2}\-\d{5})(\s+)(.*)(\s+)(Total:)(\s+)(\$(\d+\,?\d+\.?)+)|((\d{1,2})\/(\d{1,2})\/(\d{1,4}))\s+(\$(\d+\,?\.?)+)\s+(\d{1,5}BK)\s+(.*)/)
case_number = "unknown"
debtor = "unknown"
total_amount = "unknown"

combined_info.each do |line|
  # If it's a debtor, set variables, no output
  if line.at(0)
    case_number = line.at(0)
    debtor = line.at(2).strip
    total_amount = line.at(6)
    next
  end

  # A creditor, so collect data and output, note our capture indices have moved . . .
  date = line.at(8)
  amount = line.at(12)
  fund_number = line.at(14)
  creditor = line.at(15)
  empty = " "
  csv << [case_number, debtor, total_amount, empty, date, amount, fund_number, creditor]
end

您的正则表达式也可以做一些工作（例如删除不必要的捕获），但这应该可以帮助您入门。

可能还有其他方法可以以更简洁的方式适合此数据输入 - 例如在输入期间逐行识别而不是使用.scan- 但是此答案旨在建立在您现有方法的基础上。

于 2013-05-14T17:27:18.593 回答