1

我有一个字符串数组,每个字符串都是用"<x> <y>". 如果y从 a 开始'n',似乎我的程序无法找到它。

所以,不起作用的字符串是。

"w north",
"w n",
"walk n",
"walk north"

你能帮忙解释一下为什么吗?

string[] next = { "next", "ne", "nx", "nxt" };
string[] yes = { "yes", "y" };
string[] no = { "no", "n" };
string[] clear = { "clear", "c" };
string[] help = { "help", "h" };
string[] walk = 
        { 
            "w north", 
            "w south",
            "w west",
            "w east",
            "w n",
            "w s",
            "w w",
            "w e",
            "walk north",
            "walk south",
            "walk west",
            "walk east" ,
            "walk n",
            "walk s",
            "walk w",
            "walk e"
        };

//Checks if any input match the arrays
public string Input(string input)
{
    input = input.ToLower();
    if (next.Any(input.Contains))
    {
        return "next";
    }
    else if (yes.Any(input.Contains))
    {
        return "yes";
    }
    else if (no.Any(input.Contains))
    {
        return "no";
    }
    else if (clear.Any(input.Contains))
    {
        return "clear";
    }
    else if (help.Any(input.Contains))
    {
        return "help";
    }
    else if (walk.Any(input.Contains))
    {
        MessageBox.Show("test input");
        Location C_locations = new Location();
        C_locations.Change_location(input);
        return "walk";
    }
    else
    {
        return "not found";
    }
}

字符串:"w north"、和"w n",应该运行这部分代码:"walk n""walk north"

else if (walk.Any(input.Contains))
{
    MessageBox.Show( "test input" );
    Location C_locations = new Location();
    C_locations.Change_location( input );
    return "walk";
}
4

1 回答 1

4

您的代码不起作用的原因在于您的no数组的内容:它包含一个单字母字符串"n"。正是这根弦使

no.Any( input.Contains )

True对任何包含 letter 的输入字符串求值'n'

为了解决这个问题,您可以将检查移到//链walk的顶部。但是,该解决方案不会过于稳健:将被分类为,将成为,等等。ifthenelse"yellow""yes""cat""clear"

于 2013-05-14T16:15:14.120 回答