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$display = mysql_query("SELECT * FROM table_comment WHERE blogid=$theID ORDER BY comment_id DESC")or die(mysql_error());
            echo "<table border='0' align='center' width='900px' style='margin-bottom:20px;margin-top:-20px;background-color:brown;border-top-left-radius:50px;border-top-right-radius:15px;border-bottom-left-radius:15px;border-bottom-right-radius:50px;'>";
                while($r = mysql_fetch_array($display))
                {
                    echo "<tr>";
                        echo "<td align='left' style='font-size:15px;padding-left:25px;color:PowderBlue'><b style='color:LightGreen'><i>".$r['post_name']."</b></i> said:</td>";
                        echo "<td align='right' style='font-size:15px;padding-right:25px;'><b style='color:Yellow'>".$r['Time']."</b>&nbsp&nbsp;<b style='color:Orange'>".$r['Date']."</td>";
                    echo "</tr>";
                    echo "<tr>";
                        echo "<td align='justify' style='color:White;font-size:20px;padding-left:25px;'>&nbsp;&nbsp;&nbsp;&nbsp;".$r['comment_area']."</td>";
                    echo "</tr>";
                    echo "<tr>";
                        echo "<td colspan='2' align='center' style='padding-right:25px;color:Yellow'>_______________________________________________________________________________________________________</td>";
                    echo "</tr>";
                }
            echo "</table>";
            echo "</div>";

我的表格评论有这个代码，但是当我尝试在评论区域的另一边评论垃圾邮件时，没有空格，当我点击发布按钮时，我的评论中的一些文本看不到。我的桌子远远超出了原来的评论表。有人可以帮助我吗？

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1 回答 1

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您可以使用 CSS 来解决此问题。

HTML：

<div class="test">Thisisverylonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglonglongspamcomment</div>

CSS：

.test {
    word-wrap: break-word;
    overflow: hidden;
    width:250px;}

演示：http: //jsfiddle.net/NkLuW/

于 2013-05-14T10:44:06.483 回答