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我有一个包含以下字段的简单表（walkin2012）：

ID |    date    |    store   | timestamp            | custName
1  | 2013-05-08 | Plainfield | 2013-05-08 10:38:40  | cust1
2  | 2013-05-08 | Plainfield | 2013-05-08 13:38:40  | cust2
3  | 2013-05-09 | Bayport    | 2013-05-09 20:38:40  | cust3
4  | 2013-05-10 | Plainfield | 2013-05-10 17:38:40  | cust4
5  | 2013-05-10 | Bayport    | 2013-05-10 11:38:40  | cust4

我想查询该表以显示每个商店在上午 10 点到下午 1 点之间完成的记录数以及每个商店每个日期在下午之后的任何记录数，这样它就会简单地给我这个结果：

date       | store      | morning | afternoon
2013-05-08 | Plainfield | 1       | 1
2013-05-09 | Bayport    | 0       | 1
2013-05-10 | Bayport    | 1       | 0
2013-05-10 | Plainfield | 0       | 1

我得到了日期，商店和早上的工作，但我对如何子查询下午部分感到困惑。到目前为止，这是我的查询：

SELECT date, store, count(walkinID) AS Morning 
FROM walkin2012 
WHERE timestamp
BETWEEN concat_ws(' ',date,'10:00:00') AND concat_ws(' ',date,'13:00:00')  
GROUP BY date,store

任何帮助，将不胜感激。非常感谢你。

4

2 回答 2

4 
SELECT  date, 
        store, 
        SUM(timestamp BETWEEN date + interval 10 hour AND 
                              date + interval 13 hour) Morning,
        SUM(timestamp BETWEEN date + interval 13 hour AND 
                              date + interval 24 hour) Afternoon
FROM    walkin2012   
GROUP   BY date, store
于 2013-05-14T05:21:51.280 回答
0

你可以试试这个

SELECT a.date, a.store, sum(Morning) as Morning, sum(afternoon) as afternoon FROM (
  SELECT date, store, count(walkinID) AS Morning , 0 AS Afternoon
  FROM walkin2012 
  WHERE timestamp
  BETWEEN concat_ws(' ',date,'10:00:00') AND concat_ws(' ',date,'13:00:00')  
  GROUP BY date,store
  UNION
  SELECT date, store, 0 AS Morning, count(walkinID) AS Afternoon
  FROM walkin2012 
  WHERE timestamp
  < concat_ws(' ',date,'10:00:00') OR timestamp > concat_ws(' ',date,'13:00:00')  
  GROUP BY date,store
) a
GROUP BY a.date, a.store
于 2013-05-14T05:19:17.500 回答