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我在下面的 SQL 中收到此错误：

子查询返回超过 1 个值。当子查询跟随 =、!=、<、<=、>、>= 或子查询用作表达式时，这是不允许的。

有人知道我该如何解决吗？

 use character

 DECLARE @guild_codex varchar(25)
 DECLARE @character_name0 varchar(40)
 DECLARE @user_no0 varchar (25), @id varchar (25)
 DECLARE @user_no varchar (25), @group_id varchar (25), @amount varchar (25)
 DECLARE @free_amount varchar(25), @2mx_Leader varchar(3), @2mx_member varchar (3)

 SET @2mx_Leader = 700 SET @2mx_member = 500 SET @id = (SELECT id from
 [PC-ID].[Cash].[dbo].[user_cash] where free_amount LIKE 0) SET
 @user_no = (SELECT user_no from [PC-ID].[Cash].[dbo].[user_cash]
 where free_amount LIKE 0) SET @group_id = (SELECT group_id from
 [PC-ID].[Cash].[dbo].[user_cash] where free_amount LIKE 0) SET
 @amount =  (SELECT amount from [PC-ID].[Cash].[dbo].[user_cash]
 where free_amount LIKE 0) SET @free_amount =  (SELECT free_amount from
 [PC-ID].[Cash].[dbo].[user_cash] where free_amount LIKE 0) SET
 @guild_codex = (SELECT guild_code from siege_info where siege_tag LIKE'Y')

 SET @character_name0 = (SELECT character_name  from guild_char_info
 where guild_code LIKE @guild_codex and peerage_code LIKE 0) SET
 @user_no0 = (SELECT user_no from user_character where character_name
 LIKE @character_name0)   
 use cash   
 UPDATE user_cash SET
 amount=amount+@2mx_Leader WHERE user_no = @user_no0
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1 回答 1

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您的 SQL 存在多个问题

要为多个变量分配值，从同一个表中选择，使用相同的 where 子句，您将多次访问数据库，而它可以在一次调用中完成，如下所示：

   SELECT
        @id = id,
        @user_no = user_no,
        @group_id = group_id,
        @amount = amount,
        @free_amount = free_amount
    FROM [PC-ID].[Cash].[dbo].[user_cash]
    WHERE free_amount LIKE 0

您正在使用 LIKE，它可能会返回多行数据，如您的错误消息中所述。如果可以，请尝试使用 =。或者，尝试执行负责填充变量的 Select 语句，以查看是否返回了多行数据。

拉吉

于 2013-05-14T04:37:23.403 回答