2

当我尝试编译下面的代码（使用示例boost\spirit\home\lex\argument.hpp: value_setter）时，我收到以下编译器错误：

c:\program files (x86)\boost\boost_1_50\boost\range\iterator.hpp(63) : error C2039: 'type' : is not a member of 'boost::mpl::eval_if_c<C,F1,F2>'
with
[
    C=true,
    F1=boost::range_const_iterator<const char *>,
    F2=boost::range_mutable_iterator<const char *const >
]
c:\program files (x86)\boost\boost_1_50\boost\range\iterator_range_core.hpp(56) : see reference to class template instantiation 'boost::range_iterator<C>' being compiled
with
[
    C=const char *const 
]
...

没有语义动作，一切都编译得很好。这是示例：

#include <boost/spirit/include/lex_lexertl.hpp>
namespace lex = boost::spirit::lex;

template <typename Lexer>
struct my_tokens : lex::lexer<Lexer>
{
    my_tokens()
    {
        identifier = "[a-zA-Z_][a-zA-Z0-9_]*";
        this->self = identifier  [ lex::_val = "identifier" ] // problematic action
                   ;
    }
    lex::token_def<> identifier;
};

int main()
{
    typedef std::string::iterator base_iterator_type;
    typedef
        lex::lexertl::actor_lexer<lex::lexertl::token<base_iterator_type> > 
        lexer_type;

    my_tokens<lexer_type> myLexer;
    std::string str = "id1";
    base_iterator_type first = str.begin();
    bool r = lex::tokenize(first, str.end(), myLexer);

    if (!r) {
        std::string rest(first, str.end());
        std::cerr << "Lexical analysis failed\n" << "stopped at: \"" 
                  << rest << "\"\n";
    }
}

出了什么问题？如何设置/更改令牌的值？

4

1 回答 1

3

您的 token_def 应该公开预期的属性类型（编译错误表明您正在将字符串文字分配给 iterator_range）：

lex::token_def<std::string> identifier;

现在，匹配作业中的类型

this->self = identifier  [ lex::_val = std::string("identifier") ]

不要忘记更新令牌类型以反映可能的令牌属性类型集：

typedef
    lex::lexertl::actor_lexer<lex::lexertl::token<base_iterator_type,
        boost::mpl::vector<std::string> > > 
    lexer_type;

现在它应该编译：

#include <boost/spirit/include/lex_lexertl.hpp>
#include <boost/spirit/include/phoenix.hpp>
namespace lex = boost::spirit::lex;
namespace phx = boost::phoenix;

template <typename Lexer>
struct my_tokens : lex::lexer<Lexer>
{
    my_tokens()
    {
        identifier = "[a-zA-Z_][a-zA-Z0-9_]*";
        this->self = identifier  [ lex::_val = std::string("identifier") ]
                   ;
    }
    lex::token_def<std::string> identifier;
};

int main()
{
    typedef std::string::iterator base_iterator_type;
    typedef
        lex::lexertl::actor_lexer<lex::lexertl::token<base_iterator_type, boost::mpl::vector<std::string> > > 
        lexer_type;

    my_tokens<lexer_type> myLexer;
    std::string str = "id1";
    base_iterator_type first = str.begin();
    bool r = lex::tokenize(first, str.end(), myLexer);

    if (!r) {
        std::string rest(first, str.end());
        std::cerr << "Lexical analysis failed\n" << "stopped at: \"" 
                  << rest << "\"\n";
    }
}
于 2013-05-14T06:58:10.047 回答