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我是 RoR 的新手，我很难创建属于用户的授权实例。当用户不存在时它工作正常，创建用户并且它是第一次授权。但是当我尝试为现有用户创建授权时，我得到了 AssociationTypeMismatch。任何想法 ？

这是我的用户类。

class User < ActiveRecord::Base
  has_many :authorizations, :dependent => :destroy
  devise :database_authenticatable, :registerable, :recoverable, :rememberable, :trackable, :validatable
  attr_accessible :email, :password, :password_confirmation, :remember_me
end

我的授权类

class Authorization < ActiveRecord::Base
  attr_accessible :accesskey, :code, :provider_id, :refreshkey, :user_id, :authorization,     :user, :user_attributes  
  belongs_to :user
end

以及在 Authorization.create 上返回错误的方法

begin generatedauthorization
  ...
  user_email = s['email']
  #check if user already exists
  user = User.where(:email => user_email)

  if user.any?
    flash[:notice] = 'Old user'
  else
    password = 'uyflgmugmiuymmb'
    user = User.create(:email => user_email, :password => password, :password_confirmation => password)
  end
  Authorization.create(:provider_id => 1, :code => code, :refreshkey => refresh_token, :accesskey => access_token, :user => user)
end
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2 回答 2

1

代替

Authorization.create(:provider_id => 1, :code => code, :refreshkey => refresh_token, :accesskey => access_token, :user => user)

写

user.authorizations.create(:provider_id => 1, :code => code, :refreshkey => refresh_token, :accesskey => access_token)
于 2013-05-13T09:21:25.327 回答
0

替换user = User.where(:email => user_email)为user = User.find_by_email(user_email)

然后user.authorizations.create(:provider_id => 1, :code => code, :refreshkey => refresh_token, :accesskey => access_token)

#where返回Relation对象，它允许其他 ActiveRecord 方法（如order）group被链接。要按电子邮件属性搜索，建议使用find_by_email返回User对象的搜索助手。
为了使它与where：user = User.where(:email => user_email).first

于 2013-05-13T09:52:44.563 回答