67

I want to upload a csv file and process the data inside that file. What is the best method to do so? I prefer not to use php script. I did the following steps. But this method only returns the file name instead of file path.So i didnt get the desired output. 

<form id='importPfForm'>
<input type='file' name='datafile' size='20'>
<input type='button' value='IMPORT' onclick='importPortfolioFunction()'/>
</form>

function importPortfolioFunction( arg ) {
    var f = document.getElementById( 'importPfForm' );
    var fileName= f.datafile.value;   
}

So how can i get the data inside that file?

4

6 回答 6

65

下面的示例基于 html5rocks 解决方案。它使用浏览器的 FileReader() 函数。仅限较新的浏览器。

请参阅http://www.html5rocks.com/en/tutorials/file/dndfiles/#toc-reading-files

在此示例中，用户选择了一个 HTML 文件。它显示在<textarea>.

<form enctype="multipart/form-data">
<input id="upload" type=file   accept="text/html" name="files[]" size=30>
</form>

<textarea class="form-control" rows=35 cols=120 id="ms_word_filtered_html"></textarea>

<script>
function handleFileSelect(evt) {
    let files = evt.target.files; // FileList object

    // use the 1st file from the list
    let f = files[0];
    
    let reader = new FileReader();

    // Closure to capture the file information.
    reader.onload = (function(theFile) {
        return function(e) {
          
          jQuery( '#ms_word_filtered_html' ).val( e.target.result );
        };
      })(f);

      // Read in the image file as a data URL.
      reader.readAsText(f);
  }

  document.getElementById('upload').addEventListener('change', handleFileSelect, false);
</script>
于 2016-09-15T16:15:14.803 回答
36

您可以使用新的 HTML 5 文件 API 来读取文件内容

https://developer.mozilla.org/en-US/docs/Using_files_from_web_applications

但这不适用于每个浏览器，因此您可能需要服务器端后备。

于 2013-05-12T08:36:54.217 回答
23

下面的示例显示了FileReader读取上传文件内容的基本用法。这是此示例的工作 Plunker。

function init() {
  document.getElementById('fileInput').addEventListener('change', handleFileSelect, false);
}

function handleFileSelect(event) {
  const reader = new FileReader()
  reader.onload = handleFileLoad;
  reader.readAsText(event.target.files[0])
}

function handleFileLoad(event) {
  console.log(event);
  document.getElementById('fileContent').textContent = event.target.result;
}
<!DOCTYPE html>
<html>

<head>
  <script src="script.js"></script>
</head>

<body onload="init()">
  <input id="fileInput" type="file" name="file" />
  <pre id="fileContent"></pre>
</body>

</html>

于 2019-06-24T13:29:41.530 回答
4

Blob 本身存在一些新工具，您可以使用它们来读取文件内容，作为保证您不必使用旧版 FileReader

// What you need to listen for on the file input
function fileInputChange (evt) {
  for (let file of evt.target.files) {
    read(file)
  }
}

async function read(file) {
  // Read the file as text
  console.log(await file.text())
  // Read the file as ArrayBuffer to handle binary data
  console.log(new Uint8Array(await file.arrayBuffer()))
  // Abuse response to read json data
  console.log(await new Response(file).json())
  // Read large data chunk by chunk
  console.log(file.stream())
}

read(new File(['{"data": "abc"}'], 'sample.json'))

于 2021-07-30T22:35:52.450 回答
0

尝试这个

document.getElementById('myfile').addEventListener('change', function() {


          var GetFile = new FileReader();
        
           GetFile .onload=function(){
                
                // DO Somthing
          document.getElementById('output').value= GetFile.result;
        
        
        }
            
            GetFile.readAsText(this.files[0]);
        })
    <input type="file"  id="myfile">


    <textarea id="output"  rows="4" cols="50"></textarea>

于 2021-07-30T10:19:15.807 回答
-1

FileReaderJS可以为您读取文件。onLoad(e)您将事件处理程序中的文件内容作为e.target.result.

于 2018-10-11T09:25:11.003 回答