我有 2 张桌子:
S_tbl
====================
id | barcode | qty |
====================
1 | 1234 | 10 |
1 | 111 | 5 |
1 | 1234 | 10 |
K_tbl
=============================
id | barcode | qty | newQty |
=============================
1 | 1234 | 10 | 20 |
我运行这个查询:
SELECT K_Tbl.id, K_Tbl.barcode, K_Tbl.Qty, K_Tbl.NewQty
FROM K_Tbl where K_Tbl.id = 1
UNION ALL
SELECT S_Tbl.id, S_Tbl.barcode, S_Tbl.Qty, '0' as NewQty
FROM S_Tbl where S_Tbl.id = 1
我明白了:
=============================
id | barcode | qty | newQty |
=============================
1 | 1234 | 10 | 20 |
1 | 1234 | 10 | 20 |
1 | 1234 | 10 | 0 |
1 | 111 | 5 | 0 |
如何合并结果将如下所示的相同行:
=============================
id | barcode | qty | newQty |
=============================
1 | 1234 | 10 | 20 |
1 | 1234 | 10 | 20 |
1 | 111 | 5 | 0 |
编辑:
我添加行:1 | 1234 | 10 |
到 S_Tbl
我需要在查询中更改:
SELECT K_Tbl.id, K_Tbl.barcode, K_Tbl.Qty, K_Tbl.NewQty
FROM K_Tbl where K_Tbl.id = 1
UNION
SELECT S_Tbl.id, S_Tbl.barcode, S_Tbl.Qty, K_Tbl.NewQty
FROM S_Tbl
left join K_Tbl on S_Tbl.id=K_Tbl.id and S_Tbl.barcode=K_Tbl.barcode
where S_Tbl.id = 1
我会看到的
=============================
id | barcode | qty | newQty |
=============================
1 | 1234 | 10 | 20 |
1 | 1234 | 10 | 20 |
1 | 111 | 5 | 0 |
现在我看到:
=============================
id | barcode | qty | newQty |
=============================
1 | 1234 | 10 | 20 |
1 | 111 | 5 | 0 |