2

在我的页面jsp中，我有一个表单，我可以在其中将用户添加到我的数据库中，并且我使用验证器在字段为空时显示错误，但我想要做的是，当我插入主键的重复条目时在我的表中，验证器向我显示一条消息，例如此登录已被使用，而不是 Apache 出错！

这是我的用户 POJO：

package gestion.delegation.domaine;

import java.io.Serializable;

public class User implements Serializable{
    /**
     * 
     */
    private static final long serialVersionUID = 1L;
    int id;
    String nom;
    String prenom;
    String login;
    String password;
    String role;
    boolean enable;
    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
    public String getNom() {
        return nom;
    }
    public void setNom(String nom) {
        this.nom = nom;
    }
    public String getPrenom() {
        return prenom;
    }
    public void setPrenom(String prenom) {
        this.prenom = prenom;
    }
    public String getLogin() {
        return login;
    }
    public void setLogin(String login) {
        this.login = login;
    }
    public String getPassword() {
        return password;
    }
    public void setPassword(String password) {
        this.password = password;
    }
    public boolean getEnable() {
        return this.enable;
    }
    public void setEnable(boolean enable) {
        this.enable = enable;
    }

    public User(int id, String nom, String prenom, String login,
            String password, String role, boolean enable) {
        super();
        this.id = id;
        this.nom = nom;
        this.prenom = prenom;
        this.login = login;
        this.password = password;
        this.role = role;
        this.enable = enable;
    }
    public String getRole() {
        return role;
    }
    public void setRole(String role) {
        this.role = role;
    }
    public User() {
        super();
    }

}

这是我的验证器：

package gestion.delegation.validator;

import gestion.delegation.domaine.User;

import org.springframework.validation.Errors;
import org.springframework.validation.ValidationUtils;
import org.springframework.validation.Validator;

public class AddUserValidator implements Validator{

    @Override
    public boolean supports(Class<?> clazz) {

        return User.class.isAssignableFrom(clazz);
    }

    @Override
    public void validate(Object obj, Errors err) {
        ValidationUtils.rejectIfEmptyOrWhitespace(err, "nom", "name.required","Choisissez un nom");
        ValidationUtils.rejectIfEmptyOrWhitespace(err, "prenom", "prenom.required", "Choisissez un prenom");
        ValidationUtils.rejectIfEmptyOrWhitespace(err, "login", "login.required", "Choisissez un login");
        ValidationUtils.rejectIfEmptyOrWhitespace(err, "password", "password.required", "Choisissez un password");
        ValidationUtils.rejectIfEmpty(err, "role", "role.required", "Choisissez un role");

    }

}

表格 ：

<c:if test="${not empty msg_success}">
                    <div class="success">Vous avez ajouter un utilisateur avec
                        succès !</div>
</c:if>
                <form:form name="ajf"
                    action="${pageContext.request.contextPath}/ajouter_user"
                    method="post" commandName="user">

                    <table id="tabmenu">


                        <tr>
                            <td id="idtab">Nom :</td>
                            <td><form:input type="text" path="nom"
                                    class="round default-width-input" name="name_" /></td>
                            <td><form:errors path="nom" Class="errorbox" /></td>
                        </tr>
                        <tr>
                            <td id="idtab">Prénom :</td>
                            <td><form:input type="text" path="prenom" name="prenom_"
                                    class="round default-width-input" /></td>
                            <td><form:errors path="prenom" cssClass="errorbox" />
                        </tr>
                        <tr>
                            <td id="idtab">Login :</td>
                            <td><form:input type="text" path="login" name="login_"
                                    cssClass="round default-width-input" /></td>
                            <td><form:errors path="login" cssClass="errorbox" /></td>
                        </tr>

                        <tr>
                            <td id="idtab">Password :</td>
                            <td><form:input type="password" path="password" name="pass_"
                                    class="round default-width-input" /></td>
                            <td><form:errors path="password" cssClass="errorbox" /></td>

                        </tr>

                        <tr>
                            <td id="idtab">Séléctionner un rôle :</td>
                            <td><form:select path="role">
                                    <form:option value="" label="" />
                                    <form:option value="ROLE_ADMIN">Administrateur</form:option>
                                    <form:option value="ROLE_USER">Simple utilisateur</form:option>
                                </form:select></td>
                            <td><form:errors path="role" cssClass="errorbox" /></td>
                        </tr>
                        <tr>
                            <td id="idtab">Activé :</td>
                            <td><form:input type="checkbox" value="true" path="enable" />
                                Oui</td>
                        </tr>
                        <tr></tr>
                        <tr></tr>
                        <tr>
                            <td><input
                                class="button round blue image-right ic-right-arrow"
                                type="submit" value="Créer" /></td>
                            <td><input
                                class="button round blue image-right ic-right-arrow"
                                type="reset" value="Initialiser" /></td>
                        </tr>

                    </table>
                </form:form>

任何想法？

4

5 回答 5

3

在这种情况下，恐怕验证器是不够的。虽然你可以扩展你的AddUserValidator类来检查给定的用户名是否是免费的，但它在两个用户同时尝试使用相同的用户名注册的情况下不起作用——验证会通过，但是其中一个用户会得到一个来自数据库的错误。

为了保护自己免受这种情况的影响，我会将注册逻辑放在 try catch 块中，并在出现错误时向用户显示适当的消息。这将是一种应用程序级别的验证。

于 2013-05-11T12:48:34.407 回答
1

Spring 验证器只是在您将对象带入数据库之前按照规定的规则检查您的对象。它对数据库一无所知。要显示使用数据库时发生的错误，您需要手动捕获异常。

于 2013-05-11T12:53:31.860 回答
1

在您的控制器中，只需通过从模型存储库中查询来检查重复项。

@Model 实体

@Table(name = "people")
public class People {
        @Column(name = "nic")
        @NotEmpty(message = "*Please provide your nic")
        private String nic;

@Repository

    public interface PeopleRepository extends JpaRepository<People, Integer>{
        People findByNic(String nic);

    }

@控制器

 @RequestMapping(value = "/welcome", method = RequestMethod.POST)
        public ModelAndView createNewPeople(Model model,, BindingResult bindingResult) {
            ModelAndView modelAndView = new ModelAndView();
            People peopleExistsEmail = peopleService.findUserByNic(people.getNic());
            if (peopleExistsEmail != null) {
                bindingResult
                        .rejectValue("nic", "error.people",
                                "There is already a person registered with the nic provided");
            }
            if (bindingResult.hasErrors()) {
                modelAndView.setViewName("welcome");
            } else {
                peopleService.savePeople(people);
                modelAndView.addObject("successMessage", "People has been registered successfully");
                modelAndView.addObject("people", new People());

                } catch (Exception e) {
                    e.printStackTrace();
                }   
            }
            return modelAndView;
        }
于 2017-12-10T12:05:37.847 回答
0

DAO 类实现中的方法是这样的：

    public final long insert(final User user) throws MyException {
        String sql = "INSERT INTO users ....";
    String chkSql = "SELECT count(*) FROM users WHERE username=:username";
    Map namedParams = new HashMap();
    namedParams.put("username", user.getUsername());
    long newId = namedTemplate.queryForInt(chkSql, namedParams);
    if (newId > 0) {
        try {
            throw new MyException(-1);
        } catch (MyException e) {
              throw e;
        }
    }
    newId = ...;// could be generated if not inc field or triggered...
    namedParams.put("username", user.getUserName());
    ...
    ...
    namedParams.put("id", newId);
    namedTemplate.update(sql, namedParams);
    return newId;
}

像这样的MyException：

public class MyException extends Exception{
private static final long serialVersionUID = 1L;
   int a;
   public MyException(int b) {
     a=b;
   }
}

控制器：

@RequestMapping(value = "/user", method = RequestMethod.POST)
    public final ModelAndView actionUser(
        final ModelMap model,
        @ModelAttribute("myitemuser") @Valid final User user,
        final BindingResult bindResult,
        ...);
        ...
        try {
             userService.addUser(user); // or dao... ;)
             } catch (Exception e) {
                 UserValidator userValidator = new UserValidator();
               userValidator.custError(bindResult);
        }

像这样的用户验证器：

...
@Override
public final void validate(final Object object, final Errors errors) {
    User user = (User) object;
    ...
    if (user.getPassword().isEmpty()) {
        errors.rejectValue("password", "error.users.emptypass");
    }
}

public final void custError(final Errors errors){
    errors.rejectValue("username"/* or login */, "error.users.uniqname");
}
...

Ну как то так))))

于 2013-07-17T12:30:32.720 回答
0

所以这是正确的答案：

DAO 类实现中的方法是这样的：

public boolean AddUser(User user) {
        boolean t=true;
        final String User_INSERT1 = "insert into utilisateurs (login, password, nom, prenom,enable) "
                + "values (?,?,?,?,?)";
        final String User_INSERT2="insert into roles (login,role) values(?,?)";
        /*
         * On récupère et on utilisera directement le jdbcTemplate
         */
        MessageDigestPasswordEncoder encoder = new MessageDigestPasswordEncoder("SHA");
        String hash = encoder.encodePassword(user.getPassword(), "");

        final String check ="select count(*) from utilisateurs where login = ?";

       int result= getJdbcTemplate().queryForInt(check, new Object[]{String.valueOf(user.getLogin())});
        if (result==0) { 
            getJdbcTemplate()
            .update(User_INSERT1,
                    new Object[] {user.getLogin(),
                            hash, user.getNom(),
                            user.getPrenom(), user.getEnable(),
                             });
    getJdbcTemplate().update(User_INSERT2, new Object[]{user.getLogin(),user.getRole()});
       return t;
        }   

        else { t = false ; return t;}

        }

控制器：

@RequestMapping(value ="/ajouter_user", method = RequestMethod.POST)
    public String add(@ModelAttribute User us,BindingResult result,ModelMap model) {
        AddUserValidator uservalid=new AddUserValidator();

        uservalid.validate(us, result);
        if (result.hasErrors()) {
            model.addAttribute("usersystem", userservice.getAllUsers());
            return "gestionUser";
        }else {
            boolean e = userservice.AddUser(us);
            if (e==false){
                model.addAttribute("msg_failed","true");
            }
            else {
            model.addAttribute("msg_success","true");}
            model.addAttribute("usersystem", userservice.getAllUsers()); /*verifier*/
            return "gestionUser";

        }


    }

并在 jsp 文件中显示错误：

<c:if test="${not empty msg_failed}">
                    <div class="errorblock">Il existe déjà un utilisateur avec cet login </div>
</c:if>
于 2013-05-11T14:08:48.137 回答