0

考虑这个 SQL 查询：

SELECT * FROM 
( 
SELECT * FROM wp_postmeta
WHERE 
(
meta_key = 'latitude' AND meta_value *1 BETWEEN 47.3641471102 AND 47.3731524898) 
OR (meta_key = 'longitude' AND meta_value *1 BETWEEN 8.53253429117 AND 8.54583070883)
) 
AS PostMeta, wp_posts 
WHERE wp_posts.id = PostMeta.post_id order by post_id asc

它为我提供了与某些值之间的纬度或某些值之间的经度匹配的所有记录。我想要得到的是匹配这两个值的记录。但是将查询中的“OR”更改为“AND”会给我零结果。

我想我需要做一个子查询，但不知道该怎么做。

任何人？

4

1 回答 1

0

您真的只需要将纬度子查询与经度子查询分开即可。现在我有更多时间，我将更明确地修改查询：

SELECT
    /* You're only interested in the wp_posts data, right? */
    /* You don't care about the data from wp_postmeta. */
    /* Only select the data you're actually going to use. */
    /* Ideally you'd specify each column in wp_posts that you're */
    /* going to use and ignore the rest */
    p.*
FROM
    wp_posts p
        JOIN (SELECT post_id FROM wp_postmeta WHERE meta_key = 'latitude' AND CAST(meta_value AS DECIMAL) BETWEEN 47.3641471102 AND 47.3731524898) lat ON p.id = lat.post_id
        JOIN (SELECT post_id FROM wp_postmeta WHERE meta_key = 'longitude' AND CAST(meta_value AS DECIMAL) BETWEEN 8.53253429117 AND 8.54583070883) long ON p.id = long.post_id
ORDER BY
    post_id ASC

...由于没有单个 wp_postmeta 记录既是纬度又是经度，因此您不能（至少，不像这样简单）在同一个 WHERE 子句中匹配它们。因此，相反，对 wp_postmeta 表创建两个单独的调用，一个用于纬度，一个用于经度，然后强制它们都匹配（因此是INNER JOIN，而不是 a LEFT JOIN）

于 2013-05-11T11:37:39.120 回答