我有一个登录系统工作。我还有一个表单，当您选择某些内容时，数据或值将被发送到 SQL 数据库，并在不同的页面上显示表中所有发送的值。
我将如何在表格上显示发送该数据的用户？
这是我用于将表单发布到数据库的代码。
<form action="add_order.php" method="post">
<input type="hidden" name="s_table" value="$username"/>
<p><input type="checkbox" name="s_food" value="Pepsi" /><font color="gray">PEPSI® </font>
<font color="white">$2.39</font>
<p><input type="checkbox" name="s_food" value="Diet Pepsi" /><font color="gray">DIET PEPSI®</font>
<font color="white">$2.39 </font>
<p><input type="checkbox" name="s_food" value="Pepsi Max" /><font color="gray">PEPSI MAX®</font>
<font color="white">$2.39 </font>
<p><input type="checkbox" name="s_food" value="Mountain Dew" /><font color="gray">MOUNTAIN DEW®</font>
<font color="white">$2.39 </font>
<p><input type="checkbox" name="s_food" value="Sierra Mist" /><font color="gray">SIERRA MIST®</font>
<font color="white">$2.39 </font>
<p><input type="checkbox" name="s_food" value="Mug Root Beer" /><font color="gray">MUG ROOT BEER®</font>
<font color="white">$2.39 </font>
<p><input type="checkbox" name="s_food" value="Spring Water" /><font color="gray">SPRING WATER</font>
<font color="white">$2.79 </font>
<p><input type="checkbox" name="s_food" value="Perrier" /><font color="gray">PERRIER®</font>
<font color="white"> $2.79</font>
这是我的登录系统代码。
$_SESSION['username']=$_POST['username'];
//Checks if there is a login cookie
if(isset($_COOKIE['ID_my_site']))
//if there is, it logs you in and directes you to the members page
{
$username = $_COOKIE['ID_my_site'];
$pass = $_COOKIE['Key_my_site'];
$check = mysql_query("SELECT * FROM users WHERE username = '$username'")or die(mysql_error());
while($info = mysql_fetch_array( $check ))
{
if ($pass != $info['password'])
{
}
else
{
header("Location: menu.php");
}
}
}
//if the login form is submitted
if (isset($_POST['submit'])) { // if form has been submitted
// makes sure they filled it in
if(!$_POST['username'] | !$_POST['pass']) {
die('You did not fill in a required field.');
}
// checks it against the database
if (!get_magic_quotes_gpc()) {
$_POST['email'] = addslashes($_POST['email']);
}
$check = mysql_query("SELECT * FROM users WHERE username = '".$_POST['username']."'")or die(mysql_error());
//Gives error if user dosen't exist
$check2 = mysql_num_rows($check);
if ($check2 == 0) {
die('That user does not exist in our database. <a href=add.php>Click Here to Register</a>');
}
while($info = mysql_fetch_array( $check ))
{
$_POST['pass'] = stripslashes($_POST['pass']);
$info['password'] = stripslashes($info['password']);
$_POST['pass'] = md5($_POST['pass']);
//gives error if the password is wrong
if ($_POST['pass'] != $info['password']) {
die('Incorrect password, please try again.');
}
else
{
// if login is ok then we add a cookie
$_POST['username'] = stripslashes($_POST['username']);
$hour = time() + 3600;
setcookie(ID_my_site, $_POST['username'], $hour);
setcookie(Key_my_site, $_POST['pass'], $hour);
//then redirect them to the members area
header("Location: menu.php");
}
}
}
else
{
// if they are not logged in
?>
<form action="<?php echo $_SERVER['PHP_SELF']?>" method="post">
<table border="0">
<tr><td colspan=2><h1>Login</h1></td></tr>
<tr><td>Username:</td><td>
<input type="text" name="username" maxlength="40">
</td></tr>
<tr><td>Password:</td><td>
<input type="password" name="pass" maxlength="50">
</td></tr>
<tr><td colspan="2" align="right">
<input type="submit" name="submit" value="Login">
</td></tr>
</table>
</form>
<?php
}
?>
</body>
</html>
我希望能够获取我登录的用户并将该用户添加到我正在订购的饮料中并将其发送到 SQL 表并显示用户和他们订购的饮料。