c++ - How to print a vertical histogram in C++

Question

#include <iostream>
using namespace std;
int main()
{
    int a, b, c, i;
    cin >> a >> b >>  c;

    for ( i = 0;  i < a; i++)
        cout << "*" << endl;

    for ( i = 0; i < b; i++)
        cout << "*" << endl;

    for ( i = 0; i < c; i++)
        cout << "*" << endl;
}

Im aware that output is as same as:

for ( i = 0; i < a + b + c; i++ ){
cout << "*" << endl;
}

So for 2 3 1 i get:

*

*

*

*

*

*

What i want is:

     *

*    * 

*    *    *   //Horizontal distance between 2 shapes don't matter.

I've no idea about how to put cursor in the right place considering the printing must be done from up to down.

EDIT: I wasn't clear about the order of printing.I hope following example helps and also,if possible, printing of each column must be done by using a seperate function.

First loop:

*

*

Second loop:

    *

*   *

*   *

Last loop:

    *

*   *

*   *   *

Printing must be done in exactly that order.Print first column,then second and goes on like this.

Answer 1

You need to rethink your printing a little. To start with you need to find out the highest column, as this is the number of lines you will have.

I would do something like this:

int high = std::max(std::max(a, b), c);

for (int i = high; i > 0; i--)
{
    if (i <= a)
        std::cout << " * ";
    else
        std::cout << "   ";

    if (i <= b)
        std::cout << " * ";
    else
        std::cout << "   ";

    if (i <= c)
        std::cout << " * ";
    else
        std::cout << "   ";

    std::cout << std::endl;
}

If you want arbitrary number of columns, you might want to put them in a std::vector, and have a inner loop for that.

---

For an arbitrary amount of columns, you could use something like:

// Get the input
std::cout << "Please enter numbers, all on one line, and end with ENTER: ";
std::string input;
std::getline(std::cin, input);

// Parse the input into integers
std::istringstream istr(input);
std::vector<int> values(std::istream_iterator<int>(istr),
                        std::istream_iterator<int>());

// Get the max value
int max_value = *std::max_element(values.begin(), values.end());

// Print the columns
for (int current = max_value; current > 0; current--)
{
    for (const int& value : values)
    {
        if (current <= value)
            std::cout << " * ";
        else
            std::cout << "   ";
    }

    std::cout << std::endl;
}

Answer 2

Code:

#include <iostream>
using namespace std;
int f[3];
int main()
{
    int a, b, c, i;
    cin >> f[0] >> f[1] >>  f[2];

    int m = max(max(f[0],f[1]),f[2]);
    for(int i=m;i>=1;i--)
    {
        for(int j=0;j<3;j++)
            if (f[j]<i) cout <<' ';
            else cout <<'*';
        cout<<endl;
    }
}

Testing:

Input: 2 3 1
Output:
 *
**
***

Answer 3

好的代码检查一下

#include<conio.h>
void main()
{
int a[5];
int i,j,max;
clrscr();
for(i=0;i<5;i++)
{
scanf("%d",&a[i]);
max=a[0];
if(max<a[i])
max=a[i];
}
printf("\n");
for(i=0;i<max;i++)
{
putchar(max);
}
printf("\n");
printf("\n");
for(i=0;i<5;i++)
{
printf("%d \t--->\t",a[i],putchar(max));
for(j=1;j<=a[i];j++)
{
printf("*");
}
printf(" ");
printf("\n");
}
printf("\n");
for(j=max;j>0;--j)
{
putchar(max);
}
getch();`
}

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