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我在一个文件中有这些行:

101 xxx 3 yyy
102 aaa 2 bbb
103 ppp 3 qqq
104 iii 5 jjj

我想将每一行的每个元素放在一个数组中,例如

int[] par1 = {101,102,103,104}
String[] par2 = {"xxx", "aaa", "ppp", "iii"}
int[] par3 = {3,2,3,5}
String[] par4 = {"yyy", "bbb", "qqq", "jjj"}
4

2 回答 2

2

使用 Guava / Apache Commons 等阅读行:

结果是:

List<String> lines;

接下来(使用lines):

List<Integer> par1 = new ArrayList();
List<String> par2 = new ArrayList();
List<Integer> par3 = new ArrayList();
List<String> par4 = new ArrayList();

try {
    for(String line : lines) {
        String[] elements = line.split(" ");
        if(elements.length == 4) {
            par1.add(Integer.valueOf(element[0])); 
            par2.add(element[1]));
            par3.add(Integer.valueOf(element[2]));
            par4.add(element[3]));
        }
        else {
            throw new Exception("Conversion failed");
        }
    }
}
catch(NumberFormatException ex) {
    throw new Exception("Conversion failed");
} 

// Convert ArrayList to Array if you need to.
于 2013-05-10T13:04:18.730 回答
1

像这样的东西应该可以工作(没有测试)

    List<String> lines = Files.readAllLines(Paths.get("1.txt"), StandardCharsets.UTF_8);
    int[] par1 = new int[lines.size()];
    String[] par2 = new String[lines.size()];
    int[] par3 = new int[lines.size()];
    String[] par4 = new String[lines.size()];
    for(int i = 0; i < lines.size(); i++) {
        String[] a = lines.get(i).split(" +");
        par1[i] = Integer.parseInt(a[0]);
        par2[i] = a[1];
        par3[i] = Integer.parseInt(a[2]);
        par4[i] = a[4];
    }
于 2013-05-10T13:06:05.033 回答