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我有一个查询：

SELECT 
  f.name as f_name, 
  f.address as f_address, 
  f.business as f_business, 
  f.web as f_web, 
  f.id_service as f_id_service, 
  f.id_city as f_id_city, 
  f.id_firm as f_id_firm, 
  f.phone as f_phone, 
  p.name as p_name 
FROM Firm f 
  left join Price p on p.id_service=f.id_service 
    AND p.id_city=f.id_city AND p.id_firm=f.id_firm 
WHERE 
  p.id_city='73041' AND 
  p.include='1' AND 
  p.blocked='0' AND 
  f.blocked='0'AND 
  p.id_group='44' AND 
  p.id_subgroup='369' 
Group by 
  f.name 
ORDER by 
  f.name ASC

我收到以下错误：

Msg 8120, Level 16, State 1, Line 4
Column 'Firm.address' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.

为什么我会得到这个，我该如何解决？

4

1 回答 1

2

你应该考虑给你的问题一个更好的标题..

您无法在选择中访问不在您的 GROUP BY 中的列（您可能必须将它们放在聚合函数中，如 MIN(...) 或 MAX(...)）。

我不确定为什么您的查询中有 GROUP BY，因为您不进行任何聚合？

您可能希望一起删除 GROUP BY。您可能希望将所有列放在 GROUP BY 中。或者您可能希望删除 group by 并在 SQL 中的 SELECT 之后添加一个 DISTINCT 子句（删除 GROUP BY 将为每一行提供一个结果）。

我的猜测是你想要这样的 SQL：

SELECT 
    f.name as f_name, 
    f.address as f_address, 
    f.business as f_business, 
    f.web as f_web, 
    f.id_service as f_id_service, 
    f.id_city as f_id_city, 
    f.id_firm as f_id_firm, 
    f.phone as f_phone, 
    p.name as p_name, 
    SUM(p.SOMEKIND_OF_COLUMN) as sumOfPrice
FROM Firm f 
    left join Price p on p.id_service=f.id_service 
        AND p.id_city=f.id_city AND p.id_firm=f.id_firm 
WHERE p.id_city='73041' AND p.include='1' AND p.blocked='0' AND f.blocked='0'
    AND p.id_group='44' AND p.id_subgroup='369' 
Group by 
    f.name, 
    f.address, 
    f.business , 
    f.web, 
    f.id_service , 
    f.id_city , 
    f.id_firm , 
    f.phone , 
    p.name  
ORDER by f.name ASC
于 2013-05-10T08:42:57.440 回答