1

我有一张这样的表(tbl1),其中“商店 3”的销售额不正确。

**date      store       sale**
Mar, 2013   store 1     100
Apr, 2013   store 1     80
Mar, 2013   store 2     70
Mar, 2013   store 3     125
Apr, 2013   store 3     80

正确的金额在另一个表(tbl2)中:

**date      store       sale**
Mar, 2013   store 3     140
Apr, 2013   store 3     170

现在,我需要编写一个生成如下结果的查询:

**store     total_sale**
store 1     180
store 2     70
store 3     310

我尝试了不同的方式来编写 CASE 语句,但总之我弄错了。我在这里简化了真正的问题,希望得到社区的帮助。谢谢!

4

1 回答 1

2

试试这个,

SELECT  a.Store,
        COALESCE(c.TotalSale, b.TotalSale) AS TotalSale
FROM    (SELECT DISTINCT Store FROM Table1) a
        INNER JOIN
        (
            SELECT  Store, SUM(sale) TotalSale
            FROM    Table1
            GROUP   BY Store
        ) b ON a.Store = b.Store
        LEFT JOIN
        (
            SELECT  Store, SUM(sale) TotalSale
            FROM    Table2
            GROUP   BY Store
        ) c ON a.Store = c.Store
于 2013-05-10T07:20:13.613 回答