c++ - C++ typedef静态函数指针：未定义符号

Answer 1

In your cpp file you need one more line:

ffunct Class::myfunct = NULL;

The class declaration said that the variable would exist somewhere but you never gave it a definition. Since it's not part of each object it has to be defined separately.

Answer 2

Your prototype of doSomething has a return type of double, but your implementation thereof has a return type of void.

static double doSomething(...)
...
void Class::doSomething(...)

Fixing this won't clear all the errors however. You still have a few more as the other answers mention.

Answer 3

static ffunct myfunct; is a declaration

You need a definition of it also in the cpp file

ffunct Class::myfunct;

Answer 4

add one line on the top of your .cpp file:

ffunct Class::myfunct=NULL;