mysql - MySQL 两表两列 COUNT

Question

我有两张桌子

TEAMS - team_id 和 team_name（除其他外）
SCHEDULE - game_id、team_a、team_b、team_a_id、team_a_id（除其他外）

我正在尝试创建一个结果，其中我找出team_name（或team_id）出现在任一列team_a或team_b（team_a_id或team_b_id）中的次数

TEAMS
team_id team_name
1001 纽约
1011 克利夫兰
1021 底特律
1031 休斯顿

时间表
game_id team_a team_b team_a_id team_b_id
1 纽约克利夫兰 1001 1011
2 纽约底特律 1001 1021
3 克利夫兰休斯顿 1011 1031

答案：纽约 2 克利夫兰 2 底特律 1 休斯顿 1

Answer 1

单程

Select t.team_name,Sum(allteams.teamcount) as NumberOfTimes
From teams t
inner join(
select team_a_id as team_ID, 1 as teamcount From Schedule
Union 
Select team_b_id, 1 From Schedule
) allteams
on allteams.Team_ID = t.Team_ID
Group By t.team_name

Answer 2

也许

SELECT count(*)
FROM teams
WHERE $teamID IN (team_a, team_b)

Answer 3

除非我遗漏了什么，否则似乎很简单。只需选择一个计数，然后使用WHERE OR 子句。

SELECT COUNT(*)
FROM schedule
WHERE team_a = 'Team Name'
OR team_b = 'Team Name'

或者：

WHERE team_a_id = 'Team ID'
OR team_b_id = 'Team ID'

Answer 4

尝试这样的事情：

select count(*)
from teams t
join schedule s on (s.team_a = t.team_name OR s.team_b = t.team_name)