c# - C# 获取具有多个值的列表框，并将其划分为多个文本文件

Question

我很难弄清楚如何做到这一点。

我有listbox很多数据。我想拿这个listbox然后有一个按钮来保存它。

该按钮将选择放置文件的目录。之后，程序应开始将这些值保存到具有命名模式Seed1.txt、Seed2.txt等的文本文件中。

问题是，我只想将 100 个项目放入生成的每个文本文件中，直到列表完成。

为了保存我的路径：

        Stream s;
        string folderPath = string.Empty;

        using (FolderBrowserDialog fdb = new FolderBrowserDialog())
        {
            if (fdb.ShowDialog() == DialogResult.OK)
            {
                folderPath = fdb.SelectedPath;
                MessageBox.Show(folderPath);

            }

为了一次性保存所有内容，我相信这会起作用：

         int total = list_failed.Items.Count;
           for (int i = 0; i < list_failed.Items.Count; i++)
            {

                StreamWriter text = new StreamWriter(s);
                text.Write(list_failed.Items[i]);
                s.Close();

我不确定其余的。文件名可能是这样的

          string filename;
            int i = 0;
            do
            {
                filename = "Seed" + ++i + ".txt";
            } while (files.Contains(filename));

score 0 · Accepted Answer

这是您可以使用的工作示例。

        string pathname = Server.MapPath("/");
        int counter = 1;
        string file = String.Empty;

        List<string> list = new List<string>();


        //Add the list items
        for (int i = 0; i <= 1234; i++)
        {
            list.Add(String.Format("item {0}", i));
        }


        //write to file
        for (int i = 1; i < list.Count(); i++)
        {
            //generate a dynamic filename with path
            file = String.Format("{0}Seed{1}.txt", pathname, counter);

            //the using statement closes the streamwriter when it completes the process
            using (StreamWriter text = new StreamWriter(file, true))
            {
                //write the line
                text.Write(list[i]);
            }

            //check to see if the max lines have been written
            if (i == counter * 100) counter++;                
        }

score 0 · Accepted Answer

    string folderPath;
    const int ITEMS_PER_FILE=100;
    void AskUserForFolder()
    {
        folderPath = string.Empty;

        using (FolderBrowserDialog fdb = new FolderBrowserDialog())
        {
            if (fdb.ShowDialog() == DialogResult.OK)
            {
                folderPath = fdb.SelectedPath;
                // MessageBox.Show(folderPath);

            }
        }
    }

    void SaveItems(ListBox listBox, int seed)
    {

        int total = listBox.Items.Count;

        for ( int fileCount=0;fileCount<listBox.Items.Count/ITEMS_PER_FILE;++fileCount)
        {
            using (StreamWriter sw = new StreamWriter(folderPath + "\\" + GetFilePath(folderPath, "filename.txt",ref seed)))
            {
                for (int i = 0; i < listBox.Items.Count; i++)
                {
                    sw.WriteLine(listBox.Items[i+(ITEMS_PER_FILE*fileCount)]);
                }
                sw.Close();
            }
        }
    }
    //I'm not sure about the rest though. Something like this for the filenames perhaps
    /// <summary>
    /// Gets a filename that has not been used before by incrementing a number at the end of the filename
    /// </summary>
    /// <param name="seed">seed is passed in as a referrect value and acts as a starting point to itterate through the list
    /// By passing it in as a reference we can save ourselves from having to itterate unneccssarily for the start each time
    /// </param>
    /// <returns>the path of the file</returns>
    string GetFilePath(string folderpath, string fileName,string extension,ref int seed)
    {
        FileInfo fi = new FileInfo(string.Format("{0}\\{1}{2}.{3}", folderPath, fileName, seed,extension));
        while (fi.Exists)
        {
            fi = new FileInfo(string.Format("{0}\\{1}{2}.{3}", folderPath, fileName, ++seed,extension));
        }
        return fi.FullName;
    }

score 0 · Accepted Answer

试试这个迭代 ListBox 项目并将它们放入最多包含 100 个项目的文件中：

       private void writeItemsToFile(ListBox lb)
        {
        string path = @"c:\test\";
        string filename = "seed";
        int itemCounter = 0;
        int fileCounter = 1;
        StreamWriter sw = new StreamWriter(File.OpenWrite(System.IO.Path.Combine(path,string.Format(filename+"{0}.txt",fileCounter))));
        foreach (var s in lb.Items)
            {
            if (itemCounter > 100)
                {
                fileCounter++;
                itemCounter = 0;
                sw.Flush();
                sw.Close();
                sw.Dispose();
                sw = null;
                sw = new StreamWriter(File.OpenWrite(System.IO.Path.Combine(path,string.Format(filename+"{0}.txt",fileCounter))));
                }
            sw.WriteLine(s.ToString());
            itemCounter++;
            }
        if (sw != null)
            {
            sw.Flush();
            sw.Dispose();
            }
        }

c# - C# 获取具有多个值的列表框，并将其划分为多个文本文件

3 回答 3

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