1

我有一个包含 3 个字段（id、jobsprocess、percent）的表，并且想要即时计算出累积百分比，因此它是一个派生字段。

在 sql 中我会这样做，它返回 13 条记录。

set @x := 0;
SELECT ID, jobsprocess, PERCENT, (@x := @x + PERCENT) AS cumaltive
FROM `hdb`.`lookupprocess`
inner join jobsprocess on jobprocess = process_id
where projid = 1302035
order by id

我如何在 yii 中做到这一点？到目前为止，我有以下内容，但它没有给我想要的结果

$lastrun = Yii::app()->db->createCommand("
                    SELECT ID, jobsprocess, PERCENT , (:criteria = :criteria + PERCENT) AS cumulative
                    FROM `hdb`.`lookupprocess`
                    inner join jobsprocess on jobprocess = process_id
                    where projid = $projid
                    order by id " )->queryAll(true, array(':criteria'=>0));

返回 13 条记录，但累计始终为 0。

我也尝试过以下方法，但出现错误

$user = Yii::app()->db->createCommand()
    ->select('ID, jobsprocess, PERCENT , (:zero := (:zero + PERCENT)) AS cumulative')
    ->from('lookupprocess')
    ->join('jobsprocess','jobprocess = process_id')
    ->where('projid = :projid', array(':projid'=>$projid,':zero'=>0))

    ->queryAll();

它:zero作为一个字符串。

CDbCommand failed to execute the SQL statement: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ':= ('0' + PERCENT)) AS cumulative
FROM `lookupprocess`
JOIN `jobsprocess` ON job' at line 1. The SQL statement executed was: SELECT ID, jobsprocess, PERCENT , (:zero := (:zero + PERCENT)) AS cumulative
FROM `lookupprocess`
JOIN `jobsprocess` ON jobprocess = process_id
WHERE projid = :projid
4

1 回答 1

1

您可以在查询的 FROM 部分声明您的 SQL 变量：

SELECT ID, jobsprocess, PERCENT, (@x := @x + PERCENT) AS cumaltive
FROM `hdb`.`lookupprocess`, (SELECT @x=0) q
inner join jobsprocess on jobprocess = process_id
where projid = 1302035
order by id

所以，像这样：

$lastrun = Yii::app()->db->createCommand("
    SELECT ID, jobsprocess, PERCENT , (@x := @x + PERCENT) AS cumulative
    FROM `hdb`.`lookupprocess`, (SELECT @x:=0) q
    inner join jobsprocess on jobprocess = process_id
    where projid = $projid
    order by id " )->queryAll();
于 2013-05-09T21:25:01.890 回答