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对于我们使用 Dropbox 的全自动应用程序，我们需要使用“dropboxfs”（使用“pyfilesystem”的 Dropbox FS 层）自动登录 Dropbox。构造函数期望

https://github.com/btimby/fs-dropbox/blob/master/dropboxfs.py#L336

oauth 过程中的令牌密钥 + 秘密。

我们可以以某种方式自动化 oauth 过程吗？我没有任何手动交互，应用程序使用 oauth 窗口启动浏览器，并且我必须确认 oauth 访问请求。

应用程序密钥+秘密不是问题。但我只想向应用程序提供 Dropbox 用户名 + 密码，以便直接访问 Dropbox。

有什么选择吗？

4

3 回答 3

1

我遇到了同样的挑战，我通过使用名为Splinter的 Web 应用程序测试框架解决了这个问题。它允许我自动执行浏览器操作。查看文档页面。

这是我使用的代码：

from splinter import *
from dropbox import rest, session
from dropbox import client as dbclient
import time

# Initiate Dropbox API
APP_KEY = '###'
APP_SECRET = '###'
ACCESS_TYPE = 'dropbox'
sess = session.DropboxSession(APP_KEY, APP_SECRET, ACCESS_TYPE)
emailDropbox = '###'
passwordDropbox = '###'

request_token = sess.obtain_request_token()

urlDropbox = sess.build_authorize_url(request_token)

def phantomjsOAuth():
    # Target url
    print 'Target url: ', urlDropbox

    browser = Browser('phantomjs')
    print 'Starting phantomjs browser'
    print 'Visiting url'
    browser.visit(urlDropbox)

    # Email form
    print 'Is the email form present? ', browser.is_element_present_by_id('login_email')
    print 'Fill email form'
    browser.find_by_id('email-field').first.find_by_id('login_email').first.fill(emailDropbox)
    print 'Email form successfully filled'

    # Password form
    print 'Is the password form present? ', browser.is_element_present_by_id('login_password')
    print 'Fill password form'
    browser.find_by_id('login_password').first.fill(passwordDropbox)
    print 'Password form successfully filled'

    # Find login submit button
    print 'Is the "Submit" button present?', browser.is_element_present_by_name('login_submit_dummy')
    submitButton = browser.is_element_present_by_name('login_submit_dummy')

    if submitButton == True:
        print 'Pauzing for 5 seconds to avoid clicking errors'
        time.sleep(5)
        print 'Attempting to click the "Submit" button in order to login'
        browser.find_by_name('login_submit_dummy').first.click()
        print '"Submit" button successfully clicked'

        # Allow connection with Dropbox
        print 'Is the "Allow" button present?', browser.is_element_present_by_css('.freshbutton-blue')
        allowButton = browser.is_element_present_by_css('.freshbutton-blue')

        if allowButton == True:
            print 'The "Allow" button is present, attempting to click..'
            browser.find_by_css('.freshbutton-blue').click()
            print 'The "Allow" button is successfully clicked, access to Dropbox is granted.'

            dropboxCode()

        else:
            print 'The "Allow" button is not present, quitting.'
            browser.quit()

    else:
        print 'The "Submit" button was not present, quitting.'
        browser.quit()

def dropboxCode():
    # The rest of the Dropbox code
    # This will fail if the user didn't visit the above URL and hit 'Allow'
    access_token = sess.obtain_access_token(request_token)

    client = dbclient.DropboxClient(sess)
    print "linked account:", client.account_info()

    f = open('working-draft.txt')
    response = client.put_file('/magnum-opus.txt', f)
    print "uploaded:", response

phantomjsOAuth()
于 2013-07-04T13:11:21.617 回答
0

Dropbox API 当前需要 OAuth，并且这些条款禁止人们尝试将其自动化的方式：

https://www.dropbox.com/terms#acceptable_use https://www.dropbox.com/developers/reference/bestpractice

（而且你真的不应该像那样存储你的用户名/密码。）

于 2013-05-09T16:42:17.680 回答
-1

OAuth 是 Dropbox Core API 提供的唯一身份验证，您不能使用用户名 + 密码来获取访问权限。

于 2013-05-09T16:01:17.217 回答