java - SimpleAdapter arraylist 在每一行中显示相同的数据

Question

我有四个蓝牙设备用于测试获取蓝牙设备名称和地址，分别称为 deviceA , deviceB, deviceC & deviceD
我的程序可以通过 mReceiver 一个一个获取设备，但是 SimpleAdapter 数组 listrow 有问题。当我扫描新设备时，所有行都将更改为相同的名称和地址。我找不到问题在哪里。请帮忙，谢谢。

我的问题例如：

首先扫描设备A时，Result是

设备A 地址A

second 当扫描到 deviceB 时，Result 为

设备 B 地址 B

第三，扫描deviceC时，Result是deviceC AddressC

设备C 地址C

第四，再次扫描deviceB时，Result为

设备 B 地址 B

扫描 deviceD 时，结果为

设备 D 地址 D

这是我的代码：

private static BluetoothAdapter mBluetoothAdapter = null;
private static BluetoothSocket mBluetoothSocket = null;
private ListView listView;
private ArrayList<Map<String,Object>> list = null;
private SimpleAdapter adapter = null; 
private Map<String,Object> hashmap = new HashMap<String,Object>(); 

protected void onCreate(Bundle savedInstanceState) 
{
    super.onCreate(savedInstanceState);
            setContentView(R.layout.getbluetooth);
            listView = (ListView) findViewById(R.id.listView1); 
            list = new ArrayList<Map<String,Object>>(); 
            find_bluetooth();     
}

public void find_bluetooth()
{ 
        Set<BluetoothDevice> setPairedDevices = mBluetoothAdapter.getBondedDevices();

       IntentFilter filter = new IntentFilter(BluetoothDevice.ACTION_FOUND);
   registerReceiver(mReceiver, filter); 

       adapter = new impleAdapter(Diver_getEvents.this,list,R.layout.bluetooth_list,new String[]{"devicename","deviceaddress"},new int[]{R.id.devicename,R.id.deviceaddress});

       listView.setOnItemClickListener(new AdapterView.OnItemClickListener()
        {
        @Override
     public void onItemClick(AdapterView<?> arg0, View v, int position,long  id) 
        {
                      mBluetoothAdapter.cancelDiscovery();
                    }
        }

   private final BroadcastReceiver mReceiver = new BroadcastReceiver()
         {
            public void onReceive(Context context, Intent intent) 
          {
               String action = intent.getAction();
                if (BluetoothDevice.ACTION_FOUND.equals(action)) 
              {
        BluetoothDevice device = intent.getParcelableExtra(BluetoothDevice.EXTRA_DEVICE);
               String deviceBTName = device.getName();
    String deviceBaddress = device.getAddress();
    hashmap.put("devicename",deviceBTName);  
    hashmap.put("deviceaddress",deviceBaddress);  
    list.add(hashmap); 
               listView.setAdapter(adapter);
              }
         }
       }

}

score 0 · Accepted Answer

每次将其添加到列表时都必须创建一个新的 HashMap

hashmap = new HashMap<String,Object>()
// put some values to hashmap
...
...
list.add(hashmap)

java - SimpleAdapter arraylist 在每一行中显示相同的数据

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