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我有以下搜索脚本，但它似乎在 IE 中根本不起作用。它总是返回“抱歉，我们找不到使用该搜索条件的任何人......”错误。

代码如下：

<?

$getmystatus = mysql_query("SELECT status FROM members WHERE ID = '$session_memberid'");
while($getmys = mysql_fetch_array($getmystatus))
{
$mystatus = $getmys['status'];
}


?>

<script language=javascript>

function search() {

var snum = 0;

var name = $("#search_name").val();
var city = $("#search_city").val();
var country = $("#search_country").val();
var jobtitle = $("#search_jobtitle").val();
var company = $("#search_company").val();
var minage = $("#search_minage").val();
var maxage = $("#search_maxage").val();
var industry = $("#search_industry").val();
var male = $('#search_male').is(':checked'); 
var female = $('#search_female').is(':checked');
var token = $("#mtoken").val();

if(!city) { city = ''; } else {}
if(!country) { country = ''; } else {}
if(!jobtitle) { jobtitle = ''; } else {}
if(!company) { company = ''; } else {}
if(!minage) { minage = '0'; } else {}
if(!maxage) { maxage = '0'; } else {}
if(!industry) { industry = ''; } else {}


if ( name != '' ) { snum = snum+1; }
if ( city != '' ) { snum = snum+1; }
if ( country != '' ) { snum = snum+1; }
if ( jobtitle != '' ) { snum = snum+1; }
if ( company != '' ) { snum = snum+1; }
if ( minage != '0' ) { snum = snum+1; }
if ( maxage != '0' ) { snum = snum+1; }
if ( industry != '' ) { snum = snum+1; }

if ( male == true ) { snum = snum+1; }
if ( female == true ) { snum = snum+1; }

if ( snum < 1 ) {

$('#sverif').html('<font color=red>Select al least 1 type</font>');

} else {

$('#searchres_nresults').hide().html("<table border='0'><tr><td><img width=60 src='/images/loading.gif'></td><td>Searching ..</td></tr></table> ").fadeIn();
$('#sverif').html('');

var dataString = "token="+token+"&name="+name+"&city="+city+"&country="+country+"&jobtitle="+jobtitle+"&company="+company+"&minage="+minage+"&maxage="+maxage+"&industry="+industry+"&male="+male+"&female="+female;

        $.ajax({
            type: "POST",
            url: "ajax/ajsearch.php",
            async: true,
            data: dataString, 
            success: function(data) {

                $("#searchres_results").html(data);
                $("#searchres_results").css("display","block");
                var snresnum = $("#searchresults_number").html();
                if ( snresnum == '0' ) {

                    $("#searchres_nresults").delay(3000).html("<div class=t23>Sorry, we couldn't find anyone using that search criteria...</div>");

                } else {

                    $("#searchres_nresults").delay(3000).html("<div class=t23>Great news, we've found "+snresnum+" people...</div>");

                }

            }

        });


}
</script>

HTML 表单符合预期，因此我不会将它与最后一个提交按钮分开，以防万一：

<div class="profilebutton" onclick="search();">Search</div>
<div class="boxleft" id='searchres_results' style='display:none;'>
</div>
4

1 回答 1

0

要Sorry, we couldn't find anyone using that search criteria...被输出，您需要到达那行代码。这意味着那snresnum == '0'是true。

这是因为您设置了：

var snresnum = $("#searchresults_number").html();

并且$("#searchresults_number").html()是'0'。

确保带有 的元素内部的值id="searchresults_number"在ajsearch.php. 现在总是这样0。

于 2013-05-08T20:12:51.107 回答