5

如果他们的个人资料中有替代信息，我需要将一组新的替代信息合并到循环中。

这是我的循环：

foreach ($doctor->getVars() as $k => $v)
    {
    $data['doctor_'. $k] = $v;
    }

foreach ($patient->get_data() as $k=>$v)
    {
    if (is_string($v) || is_numeric($v))
        $data["patient_" . $k] = strtoupper($v);
    }

这是 $data var_dump：

Array
(
    [employee] => person
    [date] => 05/08/2013
    [datetime] => 05/08/2013 9:41:15 AM
    [department] => stuff
    [employee_ext] => 7457
    [employee_email] => 
    [barcode] => *NZS01*
    [doctor_df_code] => 09HQ
    [doctor_npi] => 1111111111
    [doctor_dea] => B4574
    [doctor_upin] => 
    [doctor_license] => 
    [doctor_phone] => (111)111-1111
    [doctor_fax] => (000)000-0000
    [doctor_fname] => UNDEFINED
    [doctor_lname] => UNDEFINED
    [doctor_title] => 
    [doctor_intake_rx_caller_id] => 
    [doctor_costco_rx_caller_id] => 
    [doctor_reorder_rx_caller_id] => 
    [doctor_address1] => 24 CABELL st
    [doctor_address2] => SUITE 10
    [doctor_city] => places
    [doctor_state] => CA
    [doctor_zip] => 91111
    [doctor_active_events] => 
    [doctor_dont_call] => 0
    [doctor_dont_fax] => 1
)

我需要将下面的数组合并到上面的数组中。这是函数 addr($dfcode) 的打印变量：

Array
(
    [0] => Array
        (
            [CODE_] => 09HQ
            [doctor_address1] => alternate addy
            [doctor_address2] => 45854
            [doctor_city] => different city
            [doctor_state] => CA
            [doctor_zip] => 963545
            [doctor_phone] => (619)111-2548
            [doctor_fax] => (157)123-4569
        )

)

我是数组合并的新手，我假设在$data['doctor_'. $k] = $v我可以列出新函数和我特别要合并的字段之后？

语法是我不确定的：

$data['doctor_'. $k] . array_merge(addr($dfcode))['doctor_address1'] = $v;

任何帮助将不胜感激，谢谢。

4

1 回答 1

12

合并两个数组的一般公式如下（将$array_m合并到$array_o）：

foreach($array_m as $key=>$value){ 
    $array_o[$key] = $value;
}

$array_o现在将包含所有元素$array_m

编辑：我刚刚在您的帖子中注意到您似乎想要使用 array_merge 函数。您还可以执行以下操作：

$array_o = array_merge($array_o, array_m);
于 2013-05-08T18:02:17.667 回答