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我正在编写一个基于手风琴风格的纸牌的 python 程序。我已经编写了上面的代码，并且在过去的几个小时里一直在玩它，但我似乎无法使循环正确运行。无论出于何种原因，它要么只运行一次循环，不再要求输入，要么运行一次，询问输入，无论我输入什么，它都会崩溃。有什么想法我在这里做错了吗？

这是我的代码：

import random

print("Command Options:")
print("1C - Play card C onto pile 1 position back, ignored if invalid")
print("3C - Play card C onto pile 3 positions back, ignored if invalid")
print("C - Count of undealt cards")
print("D - Deal next card")
print("H - Print this help screen")
print("R - Resign this game (quit early)")
print("X - Exit Program")

cards=['AC','2C','3C','4C','5C','6C','7C','8C','9C','TC','JC','QC','KC','AD','2D','3D','4D','5D','6D','7D','8D','9D','TD','JD','QD','KD','AH','2H','3H','4H','5H','6H','7H','8H','9H','TH','JH','QH','KH','AS','2S','3S','4S','5S','6S','7S','8S','9S','TS','JS','QS','KS']
random.shuffle(cards,random.random)

playable=[]
done=False
while not done:
    move=input("Enter move: ")
    move_upper=move.upper()
    if move_upper == 'D':
        playable.append(cards.pop())
        print(playable)
    if move_upper == 'X' or 'R':
        done=True

    if move_upper == 'H':
        print("Command Options:")
        print("1C - Play card C onto pile 1 position back, ignored if invalid")
        print("3C - Play card C onto pile 3 positions back, ignored if invalid")
        print("C - Count of undealt cards")
        print("D - Deal next card")
        print("H - Print this help screen")
        print("R - Resign this game (quit early)")
        print("X - Exit Program")
    if move_upper == 'C':
        k=0
        for item in cards:
            k+=1
            print(K,'cards left')
4

2 回答 2

3

您误解了如何or工作。采用：

if move_upper in ('X', 'R'):

反而。

表达式move_upper == 'X' or 'R'被解释为，并且始终考虑(move_upper == 'X') or 'R'非空字符串。因此，您本质上是在测试，然后实际上什么都不再重要了。True(move_upper == 'X') or Truemove_upper

你真的不需要在done这里使用标志变量；用于break结束循环：

while True:
    # ...

    if move_upper in ('X', 'R'):
        break
于 2013-05-08T16:52:14.340 回答
0

我目前处于代码审查的状态，所以请原谅我。

cards = [ number + suite for number in 'A23456789TJQK' for suite in 'CDHS' ]

更具可读性，这样就减少了那里出现错误的可能性。

于 2013-05-08T18:30:04.080 回答