3

我的数据库中有这两个表

  Student Table                   Student Semester Table
| Column     : Type     |       | Column     : Type     |
|------------|----------|       |------------|----------|
| student_id : integer  |       | student_id : integer  |      
| satquan    : smallint |       | semester   : integer  |
| actcomp    : smallint |       | enrolled   : boolean  | 
| entryyear  : smallint |       | major      : text     |
|-----------------------|       | college    : text     |
                                |-----------------------|

其中 student_id 是学生表中的唯一键，学生学期表中的外键。学期整数是第一学期的 1，第二学期的 2，依此类推。

我正在查询我想通过他们的入学年份（有时是他们的SAT和/或行为分数）来获取学生，然后从学生学期表中获取所有这些学生的相关数据。

目前，我的查询看起来像这样：

SELECT * FROM student_semester
WHERE student_id IN(
    SELECT student_id FROM student_semester
    WHERE student_id IN(
        SELECT student_id FROM student WHERE entryyear = 2006
    ) AND college = 'AS' AND ...
)
ORDER BY student_id, semester;

但是，当我选择约 1k 个学生时，这会导致运行相对较长的查询（400 毫秒）。根据执行计划，大部分时间都花在了哈希连接上。为了改善这一点，我在 student_semester 表中添加了 satquan、actpcomp 和 entryyear 列。这将运行查询的时间减少了约 90%，但会导致大量冗余数据。有一个更好的方法吗？

这些是我目前拥有的索引（以及 student_id 上的隐式索引）：

CREATE INDEX act_sat_entryyear ON student USING btree (entryyear, actcomp, sattotal)
CREATE INDEX student_id_major_college ON student_semester USING btree (student_id, major, college)

查询计划

QUERY PLAN
Hash Join  (cost=17311.74..35895.38 rows=81896 width=65) (actual time=121.097..326.934 rows=25680 loops=1)
  Hash Cond: (public.student_semester.student_id = public.student_semester.student_id)
  ->  Seq Scan on student_semester  (cost=0.00..14307.20 rows=698820 width=65) (actual time=0.015..154.582 rows=698820 loops=1)
  ->  Hash  (cost=17284.89..17284.89 rows=2148 width=8) (actual time=121.062..121.062 rows=1284 loops=1)
        Buckets: 1024  Batches: 1  Memory Usage: 51kB
        ->  HashAggregate  (cost=17263.41..17284.89 rows=2148 width=8) (actual time=120.708..120.871 rows=1284 loops=1)
              ->  Hash Semi Join  (cost=1026.68..17254.10 rows=3724 width=8) (actual time=4.828..119.619 rows=6184 loops=1)
                    Hash Cond: (public.student_semester.student_id = student.student_id)
                    ->  Seq Scan on student_semester  (cost=0.00..16054.25 rows=42908 width=4) (actual time=0.013..109.873 rows=42331 loops=1)
                          Filter: ((college)::text = 'AS'::text)
                    ->  Hash  (cost=988.73..988.73 rows=3036 width=4) (actual time=4.801..4.801 rows=3026 loops=1)
                          Buckets: 1024  Batches: 1  Memory Usage: 107kB
                          ->  Bitmap Heap Scan on student  (cost=71.78..988.73 rows=3036 width=4) (actual time=0.406..3.223 rows=3026 loops=1)
                                Recheck Cond: (entryyear = 2006)
                                ->  Bitmap Index Scan on student_act_sat_entryyear_index  (cost=0.00..71.03 rows=3036 width=0) (actual time=0.377..0.377 rows=3026 loops=1)
                                      Index Cond: (entryyear = 2006)
Total runtime: 327.708 ms

我误认为查询中没有 Seq Scan。我认为由于符合大学条件的行数，Seq Scan 正在完成；当我将其更改为具有较少学生的索引时，将使用索引。来源：https ://stackoverflow.com/a/5203827/880928

查询 entryyear 列包括学生学期表

SELECT * FROM student_semester
WHERE student_id IN(
    SELECT student_id FROM student_semester
    WHERE entryyear = 2006 AND collgs = 'AS'
) ORDER BY student_id, semester;

查询计划

Sort  (cost=18597.13..18800.49 rows=81343 width=65) (actual time=72.946..74.003 rows=25680 loops=1)
  Sort Key: public.student_semester.student_id, public.student_semester.semester
  Sort Method: quicksort  Memory: 3546kB
  ->  Nested Loop  (cost=9843.87..11962.91 rows=81343 width=65) (actual time=24.617..40.751 rows=25680 loops=1)
        ->  HashAggregate  (cost=9843.87..9845.73 rows=186 width=4) (actual time=24.590..24.836 rows=1284 loops=1)
              ->  Bitmap Heap Scan on student_semester  (cost=1612.75..9834.63 rows=3696 width=4) (actual time=10.401..23.637 rows=6184 loops=1)
                    Recheck Cond: (entryyear = 2006)
                    Filter: ((collgs)::text = 'AS'::text)
                    ->  Bitmap Index Scan on entryyear_act_sat_semester_enrolled_cumdeg_index  (cost=0.00..1611.82 rows=60192 width=0) (actual time=10.259..10.259 rows=60520 loops=1)
                          Index Cond: (entryyear = 2006)
        ->  Index Scan using student_id_index on student_semester  (cost=0.00..11.13 rows=20 width=65) (actual time=0.003..0.010 rows=20 loops=1284)
              Index Cond: (student_id = public.student_semester.student_id)
Total runtime: 74.938 ms
4

3 回答 3

2

您查询的干净版本是

select ss.*
from
    student s
    inner join
    student_semester ss using(student_id)
where
    s.entryyear = 2006
    and exists (
        select 1
        from student_semester
        where
            college = 'AS'
            and student_id = s.student_id
    )
order by ss.student_id, semester
于 2013-05-08T15:37:34.480 回答
2

进行查询的另一种方法是使用窗口函数。

select t.*  -- Has the extra NumMatches column.  To eliminate it, list the columns you want
from (select ss.*,
             sum(case when ss.college = 'AS' and s.entry_year = 206 then 1 else 0 end) over
                  (partition by student_id) as NumMatches
      from student_semester ss join
           student s
           on ss.student_id = s.student_id
    ) t
where NumMatches > 0;

窗口函数通常比加入聚合更快，所以我怀疑这可能会表现良好。

于 2013-05-08T17:51:05.760 回答
0

看来，你想要的是 2006 年入学并且曾经在 AS 大学上过学的学生。

第一版。

SELECT sem.*
FROM student s JOIN student_semester sem USING (student_id)
WHERE s.entry_year=2006
     AND student_id IN (SELECT student_id 
                        FROM student_semester s2 WHERE s2.college='AS')
     AND /* other criteria */
ORDER BY sem.student_id, semester;

版本二

SELECT sem.*
FROM student s JOIN student_semester sem USING (student_id)
WHERE s.entry_year=2006
     AND EXISTS 
         (SELECT 1 FROM student_semester s2 
          WHERE s2.student_id = s.student_id AND s2.college='AS')
          -- CREATE INDEX foo on student_semester(student_id, college);
     AND /* other criteria */
ORDER BY sem.student_id, semester;

我希望两者都很快，但它们是否比另一个表现更好（或完全相同的计划）是 PG 之谜。

[编辑]这是一个没有半连接的版本。我不认为它会很好地工作，因为每次学生在 AS 时它都会获得多次点击。

SELECT DISTINCT ON ( /* PK of sem */ )
FROM student s 
   JOIN student_semester sem USING (student_id) 
   JOIN student_semester s2  USING (student_id)
WHERE s.entry_year=2006
   AND s2.college='AS'
ORDER BY sem.student_id, semester;
于 2013-05-08T17:21:14.050 回答