visual-c++ - 如何让这段代码取 65 并使用 c++/cli 将其转换为二进制

Question

private: System::Void button1_Click(System::Object^  sender, System::EventArgs^  e) 
{
    int base10;
    long base2 = 0;
    base10 = Convert::ToInt32(txtBase10->Text);
    base2 = base10 / 128 * 10000000;
    base10 %= 128;

    base2 = base10 / 64 * 1000000;
    base10 %= 64;

    base2 = base10 / 32 * 100000;
    base10 %= 32;

    base2 = base10 / 16 * 10000;
    base10 %= 16;

    base2 = base10 / 8 * 1000;
    base10 %= 8;

    base2 = base10 / 4 * 100;
    base10 %= 4;

    base2 = base10 / 2 * 10;
    base10 %= 2;

    base2 = base10 / 1 * 1;
    base10 %= 1;
}

Answer 1

你不明白什么是二进制形式的数字。如果您需要将任何整数转换为它的字符串表示，您可以执行以下操作：

String base2 = Convert.ToInt32(str,2).ToString();
String base8 = Convert.ToInt32(str,8).ToString();
String base10 = Convert.ToInt32(str,10).ToString();
String base16 = Convert.ToInt32(str,16).ToString();

Answer 2

If you want it as a long and not a String, you can use this as the body of your function, it will perform better:

int base10 = Convert::ToInt32(txtBase10->Text);
long base2 = 0;

for (int mask = 0x80; mask != 0; mask >>= 1)
{
    base2 *= 10;
    if (base10 & mask) ++base2;
}

// base2 now has the number you want.

Here's an ideone with a brief testing of some values between 0 and 255 (including 65).