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这里绝对是初学者（FIRST POST），我即将完成一项任务，我必须创建一个程序，让用户创建员工工资单，然后通过姓氏、名字、员工编号等搜索来显示它们。

我有一个问题，如果我为 Nancy Davidson 创建一个记录，例如，如果我搜索 EXACTLY Nancy 或 Davidson，我可以正确输出此记录。如果我搜索 nancy 或 davidson，它不会找到它。

我正在使用一个结构来存储每个员工的详细信息，将它们写入数据文件，然后读取该文件以显示记录。

即使我搜索 NAncY，有没有办法让记录仍然显示？

这是我的按姓氏搜索功能的代码：

    //Record search by employee SURNAME only
void searchSurname(Employee data[], int row)
{
    string surname, again;
    double wholeTot=0, wholeNet=0;
    again = "y";

    while (again=="y"||again=="Y")
    {
        row=0;
        bool found = false;
        clrscr();
        cout << "Please enter Employee SURNAME : ";
        Input(surname);
        clrscr();
        cout << "Surname Search results for " << surname << ". \n\n\n";
        readFile (data, row);
        int stop=row;
        for ( row = 0; row < (stop) ; row++ )
            if (surname == data[row].surname)
            {
                deconvertDate(data[row].date);
                cout << "   ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~" << endl 
                    << "   # Employee Number - " << RIGHT(19,2) << data[row].empnum << " #" << endl 
                    << "   # Employee Surname - " << RIGHT(18,2) << data[row].surname << " #" << endl 
                    << "   # Employee Forename - " << RIGHT(17,2) << data[row].forename << " #" << endl 
                    << "   # Department Number - " << RIGHT(17,2) << data[row].dept << " #" << endl 
                    << "   # Normal Hours Worked - " << RIGHT(15,2) << data[row].hours << " #" << endl 
                    << "   # Overtime Hours Worked - " << RIGHT(13,2) << data[row].ohours << " #" << endl 
                    << "   # Pay Rate - " << RIGHT(26,2) << data[row].rate << " #" << endl
                    << "   # Gross Pay - " << RIGHT(25,2) << data[row].grosspay << " #" << endl
                    << "   # Tax - " << RIGHT(31,2) << data[row].tax << " #" << endl
                    << "   # National Insurance - " << RIGHT(16,2) << data[row].natin << " #" << endl
                    << "   # Total Deductions - " << RIGHT(18,2) << data[row].totalDeduct << " #" << endl
                    << "   # Net Pay - " << RIGHT(27,2) << data[row].net << " #" << endl
                    << "   # Week Ending - " << RIGHT(23,2) << data[row].date << " #" << endl 
                    << "   ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~" << endl << endl << endl;
                wholeTot+=data[row].grosspay;
                wholeNet+=data[row].net;

                cout << "The total recorded GROSS PAY of " << data[row].surname << " is :" << wholeTot << endl;
                cout << " and the total recorded NET PAY is :" << wholeNet << endl << endl;

                found = true;
            }
            else
                if (found = false)
                {
                    cout << "No results found for that SURNAME!" << endl;
                }
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3 回答 3

3

诀窍通常是将存储的记录和用户输入的记录转换为小写或大写。为此，您可以使用toupper或tolower

于 2013-05-08T14:00:05.510 回答
3

当你调用std::equal比较时，你可以给它一个带有比较器的第四个参数。只需编写一个不区分大小写比较的比较器：

struct CaseInsensitiveCmp
{
    bool operator()( char lhs, char rhs ) const
    {
        return ::tolower( static_cast<unsigned char>( lhs ) )
            == ::tolower( static_cast<unsigned char>( rhs ) );
    }
};

（这使用了 in 中的一个参数tolower函数<ctype.h>，对于初学者来说这是最简单的解决方案。在生产代码中，当然，您会使用std::ctypein 中的 facet
<locale>。）

于 2013-05-08T14:01:10.093 回答
2

你想做不区分大小写的比较。 strcasecmp可能是一个好的开始： http: //linux.die.net/man/3/strcasecmp

于 2013-05-08T13:58:27.293 回答