在这里，我在 mysql 中有一个问题，即如何从当前日期到一周前查找值。在这里，我编写了一个程序，它应该显示当前日期和日期前一周之间的日期。
这是我的php代码：
<?php
$hostdb = 'localhost';
$namedb = 'my_db';
$userdb = 'root';
$passdb = 'root';
try {
$conn = new PDO("mysql:host=$hostdb; dbname=$namedb", $userdb, $passdb);
$conn->exec("SET CHARACTER SET utf8"); // Sets encoding UTF-8
$currDate = date('Y-m-d H:i:s');
$date = $currDate ;
// parse about any English textual datetime description into a Unix timestamp
$ts = strtotime($date);
// calculate the number of days since Monday
$dow = date('w', $ts);
//$offset = $dow - 3;
$offset = $dow - date('d');
if ($offset < 0) {
$offset = 6;
}
// calculate timestamp for the Monday
$ts = $ts - $offset*86400;
// loop from Monday till Sunday
for ($i = 0; $i < 1; $i++, $ts += 86400){
//print date("Y-m-d l", $ts) ."</br>" . "\n";
$week = date("Y-m-d H:i:s", $ts) ."</br>";
}
$sql = "SELECT * FROM battery WHERE date BETWEEN " . $date . " AND " . $week;
$result = $conn->query($sql);
echo "<table border='1' style='font-family:arial;font-size12px;' cellspacing=1>
<tr>
<th>User Id</th>
<th>Firstname</th>
<th>LastName</th>
<th>EmailId</th>
<th>Date</th>
</tr>";
while($row = $result->fetch(PDO::FETCH_ASSOC)) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['firstname'] . "</td>";
echo "<td>" . $row['lastname'] . "</td>";
echo "<td>" . $row['emailid'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "</tr>";
}
echo "</table>";
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}
?>
这里 $date 给出当前日期， $week 给出日期前一周。我无法在这两个日期之间找到价值。请，我需要一些帮助。任何帮助将不胜感激。