3

我有一个简单的表'TABLE_1'

Org   Customer   Code   Ordered   Deleted   Confirmed

RU     Cust_1      A      1000       800        200 
RU     Cust_2      B      300        0          300
US     Cust_3      C      800        100        700
RU     Cust_4      B      100        100        0
US     Cust_5      C      400        200        200 
RU     Cust_6      B      500        300        200

现在我需要为那些行转换这个表，其中 'Deleted'<>0 like

Org   Code    Customers          Ordered   Confirmed 

RU     A      Cust_1               1000       200
RU     B      Cust_4, Cust_6       600        200
US     C      Cust_3, Cust_5       1200       900

我正在使用以下查询和功能

SELECT T1.Org,
       T1.Code,
       dbo.FUNC(T1.Code, T1.Org) AS 'Customers',
       'Ordered' = (SELECT SUM(Ordered) FROM TABLE_1 AS T2 WHERE T2.Customer = T1.Customer AND T2.Code = T1.Code AND T2.Deleted<>0),
       'Confirmed' = (SELECT SUM(Confirmed) FROM TABLE_1 AS T3 WHERE T3.Customer = T1.Customer AND T3.Code = T1.Code AND T3.Deleted<>0)
FROM TABLE_1 AS T1 
WHERE T1.Deleted <> 0

功能'FUNC'：

ALTER FUNCTION [dbo].[FUNC] (@c VARCHAR(MAX), @org VARCHAR(MAX))
RETURNS VARCHAR(MAX) AS BEGIN
DECLARE @p VARCHAR(MAX) ;
SET @p = '' ;
SELECT @p = @p + T1.Customer + ', '
FROM TABLE_1 AS T1
WHERE T1.Code = @c AND T1.Org = @org AND T1.Deleted <> 0
GROUP BY T1.Customer
RETURN SUBSTRING(@p, 1, LEN(@p) - 1)
END

我认为这不是获得结果的最佳方式，特别是如果我有一张大桌子。为此目的有更好的解决方案吗？

编辑： 表 DDL 示例

CREATE TABLE [dbo].[TABLE_1](
[Org] [nchar](10) NULL,
[Customer] [nchar](100) NULL,
[Code] [nchar](10) NULL,
[Ordered] [decimal](18,1) NULL,
[Deleted] [decimal](18,1) NULL,
[Confirmed] [decimal](18,1) NULL) 
ON [PRIMARY]
4

4 回答 4

2

无论您选择做什么，您都将面临 RBAR “问题”。然而，您可能会发现使用 FOR XML PATH('') + OUTER APPLY 而不是您的函数会更好。

如果你不知道这些，我会写一段代码来演示用法。但是您能否先提供您的表格 DDL（+ 一些行）。

这里是：

SELECT
    T1.Org
    , T1.Code
    , ISNULL(STUFF(F.Customers, 1, 2, ''), '')  AS Customers
    , SUM(T1.Ordered) OVER (PARTITION BY T1.Customer, T1.Code) AS Ordered
    , SUM(T1.Confirmed) OVER (PARTITION BY T1.Customer, T1.Code) AS Confirmed
FROM TABLE_1 AS T1
OUTER APPLY (
    SELECT
        ', ' + T2.Customer
    FROM TABLE_1 AS T2
    WHERE T2.Code = T1.Code
    AND T2.Org = T1.Org
    AND T2.Deleted <> 0
    FOR XML PATH('')
) AS F(Customers)
WHERE T1.Deleted <> 0
于 2013-05-08T08:22:04.307 回答
1

SQLFiddle 演示

SELECT
   Org,
   Code,
   STUFF(
      (SELECT ','+Customer
       FROM t WHERE Code=a.Code and Deleted<>0
       FOR XML PATH('')) , 1 , 1 , '' ),
   SUM(ordered),
   SUM(Confirmed) 

FROM 
   t A 
where Deleted<>0
group by ORG,code
于 2013-05-08T08:53:31.723 回答
1

什么是最好的可能需要对您的特定数据进行一些测试，但首先让我们修复您的原始查询以获得您在问题中按预期编写的正确结果：

SELECT T1.Org,
       T1.Code,
       dbo.FUNC(T1.Code, T1.Org) AS Customers,
       SUM(Ordered) AS Ordered,
       SUM(Confirmed) AS Confirmed
FROM TABLE_1 AS T1 
WHERE T1.Deleted <> 0
GROUP BY T1.Org, T1.Code
于 2013-05-08T08:56:39.373 回答
1

您可以执行此操作，即使您的客户名称包含 XML 控制字符，它也应该有效。

在这里提琴

SELECT
            t1.[Org],
            t1.[Code],
            STUFF(
                (
                 SELECT
                               ', ' + c.[Customer]
                     FROM
                               [TABLE_1] c
                     WHERE
                               c.[Deleted] <> 0
                         AND
                               c.[Org] = t1.[Org]
                         AND
                               c.[Code] = t1.[Code]
                     ORDER BY
                               c.[Customer]
                     FOR XML PATH (''), TYPE
                 ).value('.', 'varchar(max)'),
                 1,
                 2,
                 '') [Customers],
            SUM(t1.[Ordered]),
            SUM(t1.[Confirmed])
    FROM
            [TABLE_1] t1

    WHERE
            t1.[Deleted] <> 0
    GROUP BY
            t1.[Org],
            t1.[Code];

在性能方面，只执行两个查询并担心稍后以逗号分隔的列表表示是有意义的。您获得了相同的信息，但没有 MSSQL 无法实现的字符串聚合开销。

在这里提琴

SELECT
            t1.[Org],
            t1.[Code],
            SUM(t1.[Ordered]),
            SUM(t1.[Confirmed])
    FROM
            [TABLE_1] t1

    WHERE
            t1.[Deleted] <> 0
    GROUP BY
            t1.[Org],
            t1.[Code];

SELECT
            t1.[Org],
            t1.[Code],
            t1.[Customer]
    FROM
            [TABLE_1] t1

    WHERE
            t1.[Deleted] <> 0
    ORDER BY
            t1.[Org],
            t1.[Code],
            t1.[Customer];
于 2013-05-08T09:07:00.957 回答