3

我有相同的标签名称和不同的字符串来不同的标签名称。

这是XML。

<order>
  <ID>1001</ID> 
  <config>
    <properties>
      <entry key="Total">10</entry> 
      <entry key="Name">name</entry> 
      <entry key="Config">COMMON</entry> 
      <entry key="Delivery">15-FEBRUARY-2013</entry> 
      <entry key="Setting">name</entry> 
    </properties>
    <id>19</id> 
  </config>
  <aID>58239346</aID> 
</order>

这是我当前的代码：

public String cards(string id)
    {
        StringWriter str = new StringWriter();
        XmlTextWriter xmlWriter = new XmlTextWriter(str);
        xmlWriter.Formatting = Formatting.Indented;
        xmlWriter.WriteStartDocument();
        xmlWriter.WriteStartElement("order");
        xmlWriter.WriteElementString("ID", "1001");
        xmlWriter.WriteStartElement("config");
        xmlWriter.WriteStartElement("properties");
        /*
         * Create <entry key> at here 
         * 
         * 
         * 
         *
         */
        xmlWriter.WriteEndElement();
        xmlWriter.WriteEndElement();
        xmlWriter.WriteElementString("ClientID", id);
        xmlWriter.WriteEndElement();
        xmlWriter.WriteEndDocument();
        xmlWriter.Flush();
        xmlWriter.Close();
        return str.ToString();
    }

XMLWriter的入口标签怎么写？？？我不知道怎么写。

4

4 回答 4

7

问题似乎与<entry>标签有关；这基本上是一系列 5 个块，类似于：

xw.WriteStartElement("entry");
xw.WriteAttributeString("key", "RecordTotal");
xw.WriteString("10");
xw.WriteEndElement();

但是，您可能还想看看XmlSerializer- 可能会使这更容易：

using System;
using System.Collections.Generic;
using System.Xml.Serialization;

static class Program {
    static void Main() {
        var order = new Order {
            ClientId = 1001,
            Id = 58239346,
            Config = new OrderConfig {
                Id = 19,
                Properties = {
                    new OrderProperty { Key = "RecordTotal", Value = "10"},
                    new OrderProperty { Key = "InputFileName", Value = "name"},
                    new OrderProperty { Key = "ConfigName", Value = "COMMON_"},
                    new OrderProperty { Key = "DeliveryDate", Value = "15-FEBRUARY-2013"},
                    new OrderProperty { Key = "Qualifier", Value = "name"}
                }
            }
        };
        var ser = new XmlSerializer(typeof(Order));
        ser.Serialize(Console.Out, order);
    }
}
[XmlRoot("order")]
public class Order {
    [XmlElement("clientID", Order = 0)]
    public int ClientId { get; set; }    
    [XmlElement("config", Order = 1)]
    public OrderConfig Config { get; set; }    
    [XmlElement("orderID", Order = 2)]
    public int Id { get; set; }
}

public class OrderConfig {
    [XmlElement("id", Order = 2)]
    public int Id { get; set; }    
    private readonly List<OrderProperty> properties = new List<OrderProperty>();
    [XmlArray("properties", Order = 1), XmlArrayItem("entry")]
    public List<OrderProperty> Properties { get { return properties; } }
}

public class OrderProperty {
    [XmlAttribute("key")]
    public string Key {get;set;}
    [XmlText]
    public string Value {get;set;}
}
于 2013-05-08T08:18:15.640 回答
3

我很想为此使用 Linq-to-XML：

using System;
using System.Xml.Linq;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main()
        {
            XElement root = 
                new XElement("order",
                    new XElement("clientId", 1001),
                    new XElement("config",
                        new XElement("properties",
                            new XElement("entry", new XAttribute("key", "RecordTotal"), 10),
                            new XElement("entry", new XAttribute("key", "InputFileName"), "name"),
                            new XElement("entry", new XAttribute("key", "ConfigName"), "COMMON"),
                            new XElement("entry", new XAttribute("key", "DeliveryDate"), "15-FEBRUARY-2013"),
                            new XElement("entry", new XAttribute("key", "Qualifier"), "name")),
                        new XElement("id", 19)),
                    new XElement("orderID", 58239346)
            );

            Console.WriteLine(root);
        }
    }
}

作为比较，如果您想要多个属性元素，那么 XML 看起来像这样：

<order>
  <clientId>1001</clientId>
  <config>
    <properties>
      <property>
        <entry key="RecordTotal">10</entry>
        <entry key="InputFileName">name</entry>
        <entry key="ConfigName">COMMON</entry>
        <entry key="DeliveryDate">15-FEBRUARY-2013</entry>
        <entry key="Qualifier">name</entry>
      </property>
      <property>
        <entry key="RecordTotal">15</entry>
        <entry key="InputFileName">othername</entry>
        <entry key="ConfigName">UNCOMMON</entry>
        <entry key="DeliveryDate">23-FEBRUARY-2013</entry>
        <entry key="Qualifier">qname</entry>
      </property>
    </properties>
    <id>19</id>
  </config>
  <orderID>58239346</orderID>
</order>

您的代码可能如下所示：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Xml.Linq;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main()
        {
            XElement root = 
                new XElement("order",
                    new XElement("clientId", 1001),
                    new XElement("config",
                        new XElement("properties",
                            createEntries(getEntries())),
                        new XElement("id", 19)),
                    new XElement("orderID", 58239346)
            );

            Console.WriteLine(root);
        }

        static IEnumerable<Entry> getEntries()
        {
            yield return new Entry
            {
                RecordTotal   = 10,
                InputFileName = "name",
                ConfigName    = "COMMON",
                DeliveryDate  = "15-FEBRUARY-2013",
                Qualifier     = "name"
            };

            yield return new Entry
            {
                RecordTotal   = 15,
                InputFileName = "othername",
                ConfigName    = "UNCOMMON",
                DeliveryDate  = "23-FEBRUARY-2013",
                Qualifier     = "qname"
            };
        }

        static IEnumerable<XElement> createEntries(IEnumerable<Entry> entries)
        {
            return from entry in entries
                   select new XElement(
                       "property",
                       new XElement("entry", new XAttribute("key", "RecordTotal"),   entry.RecordTotal),
                       new XElement("entry", new XAttribute("key", "InputFileName"), entry.InputFileName),
                       new XElement("entry", new XAttribute("key", "ConfigName"),    entry.ConfigName),
                       new XElement("entry", new XAttribute("key", "DeliveryDate"),  entry.DeliveryDate),
                       new XElement("entry", new XAttribute("key", "Qualifier"),     entry.Qualifier));
        }
    }

    sealed class Entry
    {
        public int RecordTotal;
        public string InputFileName;
        public string ConfigName;
        public string DeliveryDate;
        public string Qualifier;
    }
}
于 2013-05-08T08:33:20.527 回答
2

为每个条目尝试这个：

xmlWriter.WriteStartElement("entry");
xmlWriter.WriteAttributeString("key", "RecordTotal");
xmlWriter.WriteValue(10);
xmlWriter.WriteEndElement();
于 2013-05-08T08:23:16.480 回答
0

您可以尝试以下新条目：

xmlWriter.WriteStartElement("entry");
xmlWriter.WriteAttributeString("key", "RecordTotal");
xmlWriter.WriteValue(10);
xmlWriter.WriteEndElement();

您可能想查看 XML Serizalizer。以下是与此相关的代码示例：

        try
        {
            XmlSerializer serializer = new XmlSerializer(typeof(T));
            StringWriter writer = new StringWriter();
            serializer.Serialize(writer, myClass);

            StringBuilder sb = new StringBuilder(writer.ToString());
                                            return sb.ToString();
        }
        catch (Exception ex)
        {
            throw new System.Exception("Class To XML Error: " + ex.Message);
        }
于 2013-05-08T08:25:09.333 回答