php - 计算不同日期之间的价格

Question

大家好，我是新来的，我需要关于预订酒店的帮助，我有这张桌子：

id, idhotel, room, data_start, data_end, price 

现在我需要计算同一人在多天之间搜索房间时的总价，我正在尝试此查询，但结果为 0。

$query = "SELECT room, SUM(price) FROM price WHERE idhotel='".$_GET['id']."' BETWEEN 'data_start' AND 'data_end'  
ORDER BY room";

有人可以帮助我吗？

Answer 1

如果我理解正确，您可能正在寻找这样的东西

$date_start = $_GET['date_start'];
$date_end = $_GET['date_end'];
$hotel_id = $_GET['id'];

$query = "SELECT room, 
                 SUM(price) total
            FROM tablename
           WHERE data_start >= '$date_start' 
             AND date_end <= '$date_end'
             AND idhotel = $hotel_id
           GROUP BY room";

Answer 2

我认为你需要这样的东西：

SELECT idhotel, room, price, (DATEDIFF(data_end, data_start) * price) as total FROM rooms

为了测试创建下一个表并填写它选择 * ：

create table rooms (id int not null primary key auto_increment, idhotel int, room int, data_start date, data_end date, price int);

+----+---------+------+------------+------------+-------+
| id | idhotel | room | data_start | data_end   | price |
+----+---------+------+------------+------------+-------+
|  1 |       1 |    1 | 2013-05-09 | 2013-05-12 |   100 |
|  2 |       1 |    1 | 2013-05-20 | 2013-05-20 |   100 |
+----+---------+------+------------+------------+-------+

使用下一个查询获取总成本（已修改以防止丢失一天）：

SELECT idhotel, room, price, ((DATEDIFF(data_end, data_start) + 1) * price) as total FROM rooms;

结果：

+---------+------+-------+-------+
| idhotel | room | price | total |
+---------+------+-------+-------+
|       1 |    1 |   100 |   400 |
|       1 |    1 |   100 |   100 |
+---------+------+-------+-------+

延长

如果您想获取期间的房间总和，请尝试使用以下代码：

SELECT 
    idhotel, room, SUM(total) as total_sum 
FROM 
(
    SELECT 
        idhotel, 
        room,
        price, 
        (DATEDIFF(data_end, data_start) * price) as total 
    FROM 
        rooms
) as t 
GROUP BY 
    idhotel, room;

结果：

+---------+------+-----------+
| idhotel | room | total_sum |
+---------+------+-----------+
|       1 |    1 |       150 |
+---------+------+-----------+