1

我正在尝试从 JSON（如下）中获取值并将它们插入到现有 CSV 的新列中。使用我当前的代码（也在下面），添加到新行的所有内容都是每行上的单词“Array”。如何调整我的代码以使其正常工作？另外，有没有办法为我正在创建的新列设置标题名称？

谢谢，请看下面我的代码，如果您有任何问题，请告诉我。

JSON 块：

{
 "test":{"12345":"98765","56789":"54321"},
 "control":{"99999":"987651","88888":"987652","22222":"987653","27644":"987655"}
}

当前 CSV：

userid,foo_date,bar,baz,qux,country
"12345","2013-03-14","1.72500","1","1055.74","UK"
"38726","2013-03-14",\N,"1","3430.07","UK"
"85127","2013-03-14",\N,"0","635.25","US"
"16984","2013-03-14",\N,"1","5233.09","US"

当前 PHP（根据How to add columns to CSV using PHP）：

$json = json_decode($s, true);
$json_values = array_values($json['control']);

$newCsvData = array();

if (($handle = fopen("testgroup.csv", "r")) !== FALSE) {
    while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
        $data[] = $json_values;
        $newCsvData[] = $data;
    }
    fclose($handle);
}

$handle = fopen('testgroup.csv', 'w');

foreach ($newCsvData as $line) {
   fputcsv($handle, $line);
}

fclose($handle);

$s等于 JSON blob。

生成的 CSV 应如下所示：

userid,foo_date,bar,baz,qux,country,extra
"12345","2013-03-14","1.72500","1","1055.74","UK","987651"
"38726","2013-03-14",\N,"1","3430.07","UK","987652"
"85127","2013-03-14",\N,"0","635.25","US","987653"
"16984","2013-03-14",\N,"1","5233.09","US","987655"
4

2 回答 2

2

试试这个（测试）：

$data = <<<EOF
{
 "test":{"12345":"98765","56789":"54321"},
 "control":{"99999":"987651","88888":"987652","22222":"987653","27644":"987655"}
}
EOF;

$json = json_decode($data, true);
$json_values = array_values($json['control']);
// add column header to the start of the array
array_unshift($json_values, 'extra');

// open the file in read write mode.
$fd = fopen('testgroup.csv', 'r+');
// add the last field for each record
$records = array();
while($record = fgetcsv($fd)) {
    $record []= array_shift($json_values);
    $records []= $record;
}

// clear file and set seek to start
ftruncate($fd, 0); 
fseek($fd, 0); 

// rewrite file
foreach($records as $record) {
   fputcsv($fd, $record);
}

fclose($fd);
于 2013-05-08T01:37:10.627 回答
0

另一种快速而幼稚的方法是：

$json = json_decode($s, true);
$json_values = array_values($json['control']);

$i = 0;
if (($handle = fopen("csvFile.csv", "r")) !== FALSE) {
    while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
       //seperate your header data
        $i++;
        if($i==1)
            $header = $data;
        else
            $datas[] = $data; //all the data
        $i++;
    }
    fclose($handle);
}

//adding the json now to the data based on the test value
// assuming that your json data length will be same as number of rows in csv
//you can modify the code easily to make it dynamic
$j=0;
foreach($datas as &$d){
    array_push($d, $json_values[$j]);
    $j++;       
}

//than append data in the file
$handle = fopen('testgroup.csv', 'r+');
//put the header inside the csv
fputcsv($handle, $header);

foreach ($datas as $line) {
   fputcsv($handle, $line);
}

fclose($handle);

这是您应该实施的第一种方法，一旦您能够像@hek2mgl 建议的那样找到更好的方法来执行此操作..只是想把它扔在那里....

丁斯

于 2013-05-08T01:56:19.823 回答