symfony - Symfony 子实体仅被验证为类型，跳过它自己的验证

Question

我自己使用 Symfony Validator，没有表单组件。

我有一个包含子实体的实体，目前我可以验证该字段是子实体的一个实例，但我还需要它来验证子实体的约束。

#validation.yml
# This is the entity I'm validating against, it checks the type but doesn't then validate 
# it against the child entity below. 
Greg\PropertyBundle\Entity\Property:
    properties:
        property_id:
            - NotBlank: ~
            - Type:
                type: string
        addresses:
            - All:
                - Type:
                    type: Greg\PropertyBundle\Entity\Address

# child entity
Greg\PropertyBundle\Entity\Address:
    properties:
        city:
            - NotBlank: ~
            - Type:
                type: string

要调用验证器，我将使用 DI 将其传递给我的一项服务并执行以下操作：

// Validate the data
$errorList = $this->validator->validate($data);

我还通过传入以下标志进行了尝试：

$errorList = $this->validator->validate($data, null, true, true);

Answer 1

默认情况下，不会为属性中的对象委托验证。如果您想为子对象调用验证过程，那么您应该使用特定的约束“有效”。

因此，您的验证脚本将是：

#validation.yml
# This is the entity I'm validating against, it checks the type but doesn't then validate 
# it against the child entity below. 
Greg\PropertyBundle\Entity\Property:
    properties:
        property_id:
            - NotBlank: ~
            - Type:
                type: string
        addresses:
            - All:
                - Type:
                    type: Greg\PropertyBundle\Entity\Address
            # addresses is array of entities, so use "traverse" option to validate each entity in that array
            - Valid: { traverse: true }

# child entity
Greg\PropertyBundle\Entity\Address:
    properties:
        city:
            - NotBlank: ~
            - Type:
                type: string

有关“有效”约束的更多详细信息，您可以在此处找到：http: //symfony.com/doc/current/reference/constraints/Valid.html