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我正在使用 Django 1.4 和 Python 2.7。

我正在做一些值的总和......当我这样做时，这项工作很完美：

CategoryAnswers.objects.using('mam').filter(category=cat["category"], brand=cat["brand"], category__segment_category=cat["category__segment_category"]).values('category__name', 'brand__name','brand__pk').annotate(total=Sum('answer'))

并生成查询：

    SELECT `category`.`name`, `brand`.`name`, `category_answers`.`brand_id`, SUM(`category_answers`.`answer`) AS `total` 
FROM `category_answers` 
INNER JOIN `category` 
ON (`category_answers`.`category_id` = `category`.`id`) 
INNER JOIN `brand` 
ON (`category_answers`.`brand_id` = `brand`.`id`) 
WHERE (`category_answers`.`category_id` = 6  AND 
`category_answers`.`brand_id` = 1  AND 
`category`.`segment_category_id` = 1 ) 
GROUP BY `category`.`name`, `brand`.`name`, `category_answers`.`brand_id` 
ORDER BY NULL

但是当我添加一个新值时，这不起作用：

CategoryAnswers.objects.using('mam').order_by().filter(category=cat["category"], brand=cat["brand"], category__segment_category=cat["category__segment_category"]).values('category__name','category__pk','brand__name','brand__pk').annotate(total=Sum('answer'))

看到返回的查询，问题是 django add on group by a wrong field ( category_answers. id)：

SELECT `category`.`name`, `category_answers`.`category_id`, `brand`.`name`, `category_answers`.`brand_id`, 
SUM(`category_answers`.`answer`) AS `total` 
FROM `category_answers` 
    INNER JOIN `category` 
      ON (`category_answers`.`category_id` = `category`.`id`) 
    INNER JOIN `brand` 
      ON (`category_answers`.`brand_id` = `brand`.`id`) 
WHERE (`category_answers`.`category_id` = 6  AND 
`category_answers`.`brand_id` = 1  AND 
`category`.`segment_category_id` = 1 ) 
    GROUP BY `category_answers`.`id`, `category`.`name`, `category_answers`.`category_id`, `brand`.`name`, `category_answers`.`brand_id` 
ORDER BY NULL

如果我删除任何参数这项工作，所以我不认为这是特定于问题的参数......我做错了吗？

4

1 回答 1

0

我无法解决这个问题，所以......我使用原始 SQL 查询来执行此操作：

cursor = connections["mam"].cursor()        
cursor.execute("SELECT B.name, A.category_id, A.brand_id, SUM(A.answer) AS total, C.name FROM category_answers A INNER JOIN category B ON A.category_id = B.id INNER JOIN brand C ON A.brand_id = C.id WHERE A.brand_id = %s AND A.category_id = %s AND B.segment_category_id = %s", [cat["brand"],cat["category"],cat["category__segment_category"]])
c_answers = cursor.fetchone()

这不是最好的方法，但它是有效的。:)

于 2013-05-15T14:09:29.633 回答