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我正在向 URL 发送请求 XML,并将 zip 文件接收到给定路径。有时,当这个 zip 文件的带宽很低时,我会遇到麻烦,很可能 120MB 的大小没有正确下载。并在提取 zip 文件时出错。提取也发生在代码中。当我以高带宽下载时,此文件可以毫无问题地下载。

我正在寻找一个不提高带宽的解决方案,从程序级别有没有办法下载这个 zip 文件,可能是部分或类似的东西?或者大家都拥有的任何其他解决方案都受到高度赞赏。

下载:

        url = new URL(_URL);
        sc = (HttpURLConnection) url.openConnection();
        sc.setDoInput(true);
        sc.setDoOutput(true);
        sc.setRequestMethod("POST");
        sc.connect();

        OutputStream mOstr = sc.getOutputStream();
        mOstr.write(request.getBytes());

        InputStream in = sc.getInputStream();

        FileOutputStream out = new FileOutputStream(path);

        int count;
        byte[] buffer = new byte[86384];
        while ((count = in.read(buffer,0,buffer.length)) > 0)
            out.write(buffer, 0, count);

        out.close();

提取:

try {

        ZipFile zipFile = new ZipFile(path+zFile);

        Enumeration<?> enu = zipFile.entries();

        while (enu.hasMoreElements()) {

            ZipEntry zipEntry = (ZipEntry) enu.nextElement();

            String name = path+"/data_FILES/"+zipEntry.getName();
            long size = zipEntry.getSize();
            long compressedSize = zipEntry.getCompressedSize();
            System.out.printf("name: %-20s | size: %6d | compressed size: %6d\n", name, size, compressedSize);

            File file = new File(name);

            if (name.endsWith("/")) {
                file.mkdirs();
                continue;
            }

            File parent = file.getParentFile();
            if (parent != null) {
                parent.mkdirs();
            }

            InputStream is = zipFile.getInputStream(zipEntry);

            FileOutputStream fos = new FileOutputStream(file);

            byte[] bytes = new byte[86384];
            int length;

            while ((length = is.read(bytes)) >= 0) {
                fos.write(bytes, 0, length);
            }
            is.close();
            fos.close();

        }
        zipFile.close();

    } catch (Exception e) {
        log("Error in extracting zip file ");
        e.printStackTrace();
    }
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