我是一个使用 shell 脚本的新手,一直在尝试编写一些脚本并让我的简单应用程序运行。虽然我可以启动应用程序,但我无法停止或重新启动它,因为它存储了脚本本身的 PID,而我需要存储被调用脚本的 PID。这是我正在运行以获取 PID 的脚本:
#!/bin/sh
JAVA_BIN=/usr/local/jdk7/jre/bin/java
test -x $JAVA_BIN || { echo "$JAVA_BIN not installed";
if [ "$1" = "stop" ]; then exit 0;
else exit 5; fi; }
# Check for existence of needed script file
NEW_SCRIPT=/usr/local/me/myscript.sh
test -r $NEW_SCRIPT|| { echo "$NEW_SCRIPT does not exist";
if [ "$1" = "stop" ]; then exit 0;
else exit 6; fi; }
PID_FILE=/var/run/newd.pid
USER=newuser
HOME_DIR=/usr/local/me
LOG_FILE=/var/log/newd.log
HOST_NAME=some.hostname.com
case "$1" in
start)
echo "Starting newd..."
cd ${HOME_DIR} || ( \
echo "can't cd to homedir"; exit 1
)
sudo -u ${USER} ${NEW_SCRIPT} >> ${LOG_FILE} 2>&1 &
echo "PID: "
echo $!
echo "\n"
echo $! > ${PID_FILE} || (
echo "error storing pid to ${PID_FILE}"; exit 1
)
;;
stop)
echo "Shutting down newd..."
/bin/kill `cat ${PID_FILE}`
;;
restart)
$0 stop
sleep 5
$0 start
;;
status)
echo "Checking for service newd..."
statc=$(curl -I http://${HOST_NAME}:8080/test/url | head -n1 | grep HTTP | awk '{print $2}')
if [ "$statc" != "200" ]; then
echo "down"
exit 1
fi
echo "OK"
#ps u -p `cat ${PID}`
exit 0
;;
*)
echo "Usage: $0 {start|stop|status|restart}"
exit 1
;;
esac
rc_exit
使用 start 命令调用此脚本后,它会显示 PID,在这种情况下假设为 3,ps 输出如下所示:
root 3 sudo -u me /usr/local/me/myscript.sh
me 6 /bin/sh /usr/local/me/myscript.sh
me 7 PID which I want
因为我将 PID 存储为 3,然后我尝试停止应用程序,但它失败了,因为我想停止的应用程序有 7,而不是 3
任何人都可以帮助我脚本的哪一部分破坏了预期的 PID?