2

I'm parsing a xml into an object using Simple Framework. The problem is that the xml has elements with the same name but in different paths.

XML:

<prestashop>
 <products>
   <product>
    <name>
       <language id="1"> name </language>
    </name>
    <description>
      <language id="1"> description </language>
    </description>
    <description_short>
      <language id="1"> desc </language>
    </description_short>
  </product>
 </products>
</prestashop>

my class is mapped like this:

@Root(name="prestashop")
public class Product{
    @Element(name="language")
    @Path("products/product/description_short[1]")
    private String shortDesc;

    @Element(name="language")
    @Path("products/product/description[1]")
    private String longDesc;

    @Element(name="language")
    @Path("products/product/name[1]")
    private String name;
}

But during the deserialization, it gives me the exception:

  org.simpleframework.xml.core.PersistenceException: 
Element 'language' is already used with @org.simpleframework.xml.Element(data=false, name=language, required=true, type=void) 
on field 'name' private java.lang.String model.Product.name at line 8

How can i map tags with the same name but in different paths?

if I serialize the product object it gives me the correct XML structure:

<prestashop xmlns="http://www.w3.org/1999/xlink">
    <products>
       <product>
          <description_short>
             <language>short</language>
          </description_short>
          <id_default_image href="path"/>
          <description>
             <language>long</language>
          </description>
          <name>
             <language>aaa</language>
          </name>
          <price>10.0</price>
          <id>1</id>
       </product>
    </products>
 </prestashop>

Im deserializing like this:

product = new Product();
InputStream in = res.getResponse();
Serializer serializer = new Persister();
serializer.read(product, in,false);
4

1 回答 1

3

这是一个如何映射类的示例：

（示例-）类：

@Root(name = "product")
public class Product
{
    @Path(value = "name")
    @Element(name = "language")
    private String name;

    @Path(value = "description")
    @Element(name = "language")
    private String description;

    @Path(value = "description_short")
    @Element(name = "language")
    private String desc;


    // ...

    /* For testing only */
    @Override
    public String toString()
    {
        return "Product{" + "name=" + name + ", description=" + description + ", desc=" + desc + '}';
    }
}

（我没有完整的实现，但我希望我的例子是相似的）

输入 XML：

<product>
    <name>
        <language id="1"> name </language>
    </name>
    <description>
        <language id="1"> description </language>
    </description>
    <description_short>
        <language id="1"> desc </language>
    </description_short>
</product>

注意<product> </product>标签和"forid属性（没有它们可能会失败）

测试代码：

final File f = new File("test.xml"); // Input file

Serializer ser = new Persister();
Product p = ser.read(Product.class, f); // deserialize the class


System.out.println(p); // output - thats why i've implemented the 'toString()' method

输出：

Product{name= name , description= description , desc= desc }

（空白是由xml引起的）

看起来您想要序列化/反序列化一个列表，所以products应该是一个列表（可以内联）并且product是上面的类。

编辑：

Product班级：

@Root(name = "product")
public class Product
{
    @Path(value = "name")
    @Element(name = "language")
    private String name;

    @Path(value = "description")
    @Element(name = "language")
    private String description;

    @Path(value = "description_short")
    @Element(name = "language")
    private String desc;

    @Element(name = "id_default_image")
    private AttributedElement idDefaultImage;

    @Element(name = "price")
    private double price;

    @Element(name = "id")
    private int id;



    @Override
    public String toString()
    {
        return "Product{" + "name=" + name + ", description=" + description 
                + ", desc=" + desc + ", idDefaultImage=" + idDefaultImage 
                + ", price=" + price + ", id=" + id + '}';
    }



    @Root(name = "AttributedElement")
    static class AttributedElement
    {
        @Attribute(name = "href")
        private String value;


        public AttributedElement(String value)
        {
            this.value = value;
        }

        private AttributedElement()
        {
            /* Empty constructor required here */
        }


        @Override
        public String toString()
        {
            return value;
        }
    }

}

注意：我使用该内部类作为助手来为图像元素获取正确的 xml 结构。

现在，接下来有一个围绕Product. 但是，我将其作为地图实现，如果只有一种产品，您可以使用简单的类而不是列表。

Prestashop班级：

@Root(name = "prestashop")
public class Prestashop
{
    @ElementList(name = "products", empty = false, required = true)
    private ArrayList<Product> products;


    public Prestashop()
    {
        this.products = new ArrayList<>();
    }


    /* Some list methods */

    public void add(Product p)
    {
        products.add(p);
    }

    public Product get(int index)
    {
        return products.get(index);
    }

    public Product first()
    {
        return products.get(0);
    }

}

注意：有关我为什么不在List<Product>此处使用的解释，请参阅此答案。

测试代码：

Serializer ser = new Persister();

Prestashop shop = ser.read(Prestashop.class, f);
System.out.println(shop.first());

输入 XML：

<prestashop xmlns="http://www.w3.org/1999/xlink">
    <products>
       <product>
          <description_short>
             <language>short</language>
          </description_short>
          <id_default_image href="path"/>
          <description>
             <language>long</language>
          </description>
          <name>
             <language>aaa</language>
          </name>
          <price>10.0</price>
          <id>1</id>
       </product>
    </products>
 </prestashop>

（您的第二个问题）

最后...

输出：

Product{name=aaa, description=long, desc=short, idDefaultImage=path, price=10.0, id=1}
于 2013-05-07T14:37:45.963 回答