php - 如何在php中加入2个mysql查询作为hetml返回值

Question

这些查询单独运行 100%

查询1

SELECT year_entered, 
   month_entered,
   IFNULL(amount - @n, 0) amount_diff,
   @n := amount current_amount
  FROM
 (SELECT YEAR(date_entered) year_entered, 
     MONTHNAME(date_entered) month_entered, 
     SUM(amount) amount
FROM opportunities
INNER JOIN opportunities_cstm
ON ( opportunities.id = opportunities_cstm.id_c)
WHERE 
YEAR(opportunities.date_entered) >= YEAR(CURDATE())
AND  (`opportunities`.`deleted` <> '1') AND 
(opportunities_cstm.interest_level_c = 'Ultraspin'
OR 
opportunities_cstm.interest_level_c = 'Mycelx')
GROUP BY YEAR(date_entered), MONTH(date_entered)) q, 
(SELECT @n := NULL) n

查询 2

SELECT year_entered, 
   month_entered,
   IFNULL(id - @n, 0) id_diff,
       @n := id current_id
  FROM
 (SELECT YEAR(date_entered) year_entered, 
         MONTHNAME(date_entered) month_entered, 
         COUNT(id) id
    FROM opportunities
    INNER JOIN opportunities_cstm
    ON ( opportunities.id = opportunities_cstm.id_c)
 WHERE 
 YEAR(opportunities.date_entered) >= YEAR(CURDATE())
 AND  (`opportunities`.`deleted` <> '1') AND 
 (opportunities_cstm.interest_level_c = 'Ultraspin'
 OR 
 opportunities_cstm.interest_level_c = 'Mycelx')
   GROUP BY YEAR(date_entered), MONTH(date_entered)) q, 
 (SELECT @n := NULL) n
 ON year_entered = year_entered

我需要一个查询中的数量差异和计数差异如何，想要用户 jasper 报告来报告这一点，或者是否有人可以帮助 php 返回行？

只是不知道如何获取两个查询并将它们彼此相邻返回

Answer 1

尝试这个：

    SELECT year_entered, 
   month_entered,
   query1.amount_diff,
   query2.id_diff FROM
        (SELECT year_entered, 
           month_entered,
           IFNULL(amount - @n, 0) amount_diff,
           @n := amount current_amount
          FROM
         (SELECT YEAR(date_entered) year_entered, 
             MONTHNAME(date_entered) month_entered, 
             SUM(amount) amount
        FROM opportunities
        INNER JOIN opportunities_cstm
        ON ( opportunities.id = opportunities_cstm.id_c)
        WHERE 
        YEAR(opportunities.date_entered) >= YEAR(CURDATE())
        AND  (`opportunities`.`deleted` <> '1') AND 
        (opportunities_cstm.interest_level_c = 'Ultraspin'
        OR 
        opportunities_cstm.interest_level_c = 'Mycelx')
        GROUP BY YEAR(date_entered), MONTH(date_entered)) q, 
        (SELECT @n := NULL) n) query1 JOIN (
            SELECT year_entered, 
               month_entered,
               IFNULL(id - @n, 0) id_diff,
                   @n := id current_id
              FROM
             (SELECT YEAR(date_entered) year_entered, 
                     MONTHNAME(date_entered) month_entered, 
                     COUNT(id) id
                FROM opportunities
                INNER JOIN opportunities_cstm
                ON ( opportunities.id = opportunities_cstm.id_c)
             WHERE 
             YEAR(opportunities.date_entered) >= YEAR(CURDATE())
             AND  (`opportunities`.`deleted` <> '1') AND 
             (opportunities_cstm.interest_level_c = 'Ultraspin'
             OR 
             opportunities_cstm.interest_level_c = 'Mycelx')
               GROUP BY YEAR(date_entered), MONTH(date_entered)) q, 
             (SELECT @n := NULL) n
             ON year_entered = year_entered
        ) query2 ON query1.year_entered = query2.year_entered AND query1.month_entered = query2.month_entered

Answer 2

SELECT year_entered, 
       month_entered,
       IFNULL(amount - @n, 0) amount_diff,
       IFNULL(id - @a, 0) id_diff,
       @n := amount current_amount,
       @i := id current_id
FROM (SELECT YEAR(date_entered) year_entered, 
             MONTHNAME(date_entered) month_entered, 
             SUM(amount) amount,
             COUNT(id) id
      FROM opportunities
      INNER JOIN opportunities_cstm
      ON ( opportunities.id = opportunities_cstm.id_c)
      WHERE YEAR(opportunities.date_entered) >= YEAR(CURDATE())
            AND  (`opportunities`.`deleted` <> '1')
            AND (opportunities_cstm.interest_level_c = 'Ultraspin'
            OR opportunities_cstm.interest_level_c = 'Mycelx')
      GROUP BY YEAR(date_entered), MONTH(date_entered)) q,
     (SELECT @n := NULL, @i := NULL) n