java - 在 Java 中查找 char 数组的大小时出错

Question

我刚开始Java，我不明白为什么这段代码：

char WORDS[][] = {"jazz", "buzz", "hajj", "fuzz", "jinx", "jazzy", "fuzzy", "faffs", "fizzy", "jiffs", "jazzed", "buzzed", "jazzes", "faffed", "fizzed", "jazzing", "buzzing", "jazzier", "faffing", "fuzzing"};
char comp[] = WORDS[rand.nextInt(WORDS.length)];
char compHidden[comp.length];

产生此错误：

- Syntax error on token "[", = expected
- Type mismatch: cannot convert from int 
 to char
- Syntax error on token "]", delete this 
 token

都在第三行。为什么是这样？还有另一种方法可以找到 char 数组的长度吗？

Answer 1

这里需要一个分配，例如：

char compHidden[] = new char[comp.length];

Answer 2

该WORDS数组没有被实例化为多维数组，而是被实例化为常规数组，char[]并且应该这样声明。数组的类型也不应该是char[]，而是应该String[]给出分配的数组类型。

改变：

char WORDS[][] = {"jazz", "buzz", "hajj", "fuzz", "jinx", "jazzy", "fuzzy", "faffs", "fizzy", "jiffs", "jazzed", "buzzed", "jazzes", "faffed", "fizzed", "jazzing", "buzzing", "jazzier", "faffing", "fuzzing"};

至

String WORDS[] = {"jazz", "buzz", "hajj", "fuzz", "jinx", "jazzy", "fuzzy", "faffs", "fizzy", "jiffs", "jazzed", "buzzed", "jazzes", "faffed", "fizzed", "jazzing", "buzzing", "jazzier", "faffing", "fuzzing"};