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所以我有三张桌子。CUSTOMER(CustomerID,LastName,FirstName),PURCHASE(PurchaseID,ItemName)和 TRANSACTION(CustomerIDPurchaseID,Date)。

我遇到的问题是我需要获得专门购买“油漆”和“书籍”这两个项目的客户的全名,但是当我运行我的代码时,什么也没有出现。这是我所拥有的:

SELECT CUSTOMER.FirstName, CUSTOMER.LastName
FROM CUSTOMER, PURCHASE
WHERE PURCHASE.Item = 'Paint' AND PURCHASE.Item = 'Books'
GROUP BY CUSTOMER.LastName, CUSTOMER.FirstName;

请帮忙,我对此很陌生,真的很想得到一些帮助。

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4 回答 4

5

这种类型的问题称为Relational Division

SELECT  CUSTOMER.FirstName, CUSTOMER.LastName
FROM    CUSTOMER    
        INNER JOIN TRANSACTION
            ON CUSTOMER.CustomerID = TRANSACTION.CustomerID
        INNER JOIN PURCHASE
            ON TRANSACTION.PurchaseID = PURCHASE.PurchaseID
WHERE   PURCHASE.Item IN ('Paint', 'Books')  -- list all items here
GROUP   BY CUSTOMER.LastName, CUSTOMER.FirstName
HAVING  COUNT(DISTINCT PURCHASE.Item) = 2 -- the total number of items searched

如果对每个事务UNIQUE都强制执行约束,您可以使用ItemName*

SELECT  CUSTOMER.FirstName, CUSTOMER.LastName
FROM    CUSTOMER    
        INNER JOIN TRANSACTION
            ON CUSTOMER.CustomerID = TRANSACTION.CustomerID
        INNER JOIN PURCHASE
            ON TRANSACTION.PurchaseID = PURCHASE.PurchaseID
WHERE   PURCHASE.Item IN ('Paint', 'Books')
GROUP   BY CUSTOMER.LastName, CUSTOMER.FirstName
HAVING  COUNT(*) = 2
于 2013-05-06T07:52:48.787 回答
1

无连接..

SELECT DISTINCT CUSTOMER.FirstName, CUSTOMER.LastName
FROM CUSTOMER A 
JOIN TRANSACTION B
ON A.CUSTOMERID=B.CUSTOMERID
JOIN PURCHASE C
ON B.PURCHASEID=C.PURCHASEID AND C.ITEM='Paint'
JOIN PURCHASE D 
ON B.PURCHASEID=D.PURCHASEID AND D.C.Item = 'Books'
于 2013-05-06T07:52:33.903 回答
0

你需要JOIN表。尝试

SELECT CUSTOMER.FirstName, CUSTOMER.LastName
FROM   CUSTOMER 
       INNER JOIN TRANSACTION ON TRANSACTION.CustomerID=CUSTOMER.CustomerID 
       INNER JOIN PURCHASE ON PURCHASE.PurchaseID=TRANSACTION.PurchaseID
WHERE PURCHASE.Item = 'Paint' OR PURCHASE.Item = 'Books'
GROUP BY CUSTOMER.LastName, CUSTOMER.FirstName
HAVING COUNT(DISTINCT PURCHASE.Item) >= 2;
于 2013-05-06T07:54:38.490 回答
0
SELECT CUSTOMER.FirstName, CUSTOMER.LastName
FROM CUSTOMER C, PURCHASE P, TRANSACTION T
WHERE
C.CUSTOMERID = T.CUSTOMERID AND T.PurchaseID = P.PurchaseID
AND P.Item IN ('Paint','Books')

This is pseudo code. Try it out by yourselves.

于 2013-05-06T07:58:22.147 回答