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我已经通过 GCM 使用 ASP.net C# 向 Android 手机发送了推送通知。

但是我尝试了不同类型的代码,但所有 arr 都返回 Missing Registration 错误,所以请帮助我。

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2 回答 2

0

尝试PushSharp。这很简单。并查看此说明 -如何使用 PushSharp 配置和发送 GCM Google 云消息推送通知

var push = new PushBroker();

//Registering the GCM Service and sending an Android Notification
push.RegisterGcmService(new GcmPushChannelSettings("theauthorizationtokenhere"));
//Fluent construction of an Android GCM Notification
//IMPORTANT: For Android you MUST use your own RegistrationId here that gets generated within your Android app itself!
push.QueueNotification(new GcmNotification().ForDeviceRegistrationId("DEVICE REGISTRATION ID HERE")
                      .WithJson("{\"alert\":\"Hello World!\",\"badge\":7,\"sound\":\"sound.caf\"}"));

您可以通过nuget安装它。

于 2013-05-06T05:51:29.723 回答
0
 public class GCMSNS
{
    public static string SendGCMNotification(string deviceId, string message)
    {
        string GoogleAppID = "XYxxxxxxxxxxxxxxxxxxxx";//This is API Key Server
        var SENDER_ID = "11111111111111"; //This is Google Project Id
        var value = message;
        WebRequest tRequest;
        tRequest = WebRequest.Create("https://android.googleapis.com/gcm/send");
        tRequest.Method = "post";
        tRequest.ContentType = " application/x-www-form-urlencoded;charset=UTF-8";
        tRequest.Headers.Add(string.Format("Authorization: key={0}", GoogleAppID));

        tRequest.Headers.Add(string.Format("Sender: id={0}", SENDER_ID));

        string postData = "collapse_key=score_update&time_to_live=108&delay_while_idle=1&data.message=" + value + "&data.time=" +
        System.DateTime.Now.ToString() + "&registration_id=" + deviceId + "";
        Console.WriteLine(postData);
        Byte[] byteArray = Encoding.UTF8.GetBytes(postData);
        tRequest.ContentLength = byteArray.Length;

        Stream dataStream = tRequest.GetRequestStream();
        dataStream.Write(byteArray, 0, byteArray.Length);
        dataStream.Close();

        WebResponse tResponse = tRequest.GetResponse();

        dataStream = tResponse.GetResponseStream();

        StreamReader tReader = new StreamReader(dataStream);

        String sResponseFromServer = tReader.ReadToEnd();

        tReader.Close();
        dataStream.Close();
        tResponse.Close();
        return sResponseFromServer;
    }
}
于 2014-12-18T17:36:30.073 回答