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我不确定这是否是一个愚蠢的问题,所以请在这里耐心等待。反正我有两个UIAccelerationValue's。当我单独NSLog他们的结果时,我分别得到这样的值:

1. Value: -0.016186

2. Value2: -0.033460

但是,当我将两者相加或相减UIAccelerationValue's时,我得到如下值:

Value: -571.142049
Value: -1085.174017
Value: -2061.834754
Value: -3917.490156
Value: -7443.235420
Value: -14142.151420

如您所见,这些值只是呈指数级增长。

UIAccelerationValues无论如何,如果没有我现在得到的结果,我怎么能只是简单地将两者相加或相减呢?

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2 回答 2

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我认为您正在存储加法/减法的结果,并且一遍又一遍地进行加法/减法,因此增加了较大的值

UIAccelerationValue 只是一个双精度值(参见 UIAccelerometer.h):

typedef double UIAccelerationValue;

通过以下示例,您将获得预期的输出:

UIAccelerationValue xOne = -0.016186;
UIAccelerationValue xTwo = -0.033460;

NSLog(@"%f", xOne + xTwo); // prints out -0.049646
NSLog(@"%f", xOne - xTwo); // prints out 0.017274
于 2013-05-15T14:55:56.810 回答
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我不是 UIAcceleration 方面的专家,但这里是示例代码中的一个示例。希望能帮助到你。

#define kAccelerometerFrequency        50.0 //Hz
#define kFilteringFactor 0.1


UIAccelerationValue gravX;
UIAccelerationValue gravY;
UIAccelerationValue gravZ;
gravX = (acceleration.x * kFilteringFactor) + (gravX * (1.0 - kFilteringFactor));
gravY = (acceleration.y * kFilteringFactor) + (gravY * (1.0 - kFilteringFactor));
gravZ = (acceleration.z * kFilteringFactor) + (gravZ * (1.0 - kFilteringFactor));

UIAccelerationValue accelX = acceleration.x - ( (acceleration.x * kFilteringFactor) + (gravX * (1.0 - kFilteringFactor)) );

UIAccelerationValue accelY = acceleration.y - ( (acceleration.y * kFilteringFactor) + (gravY * (1.0 - kFilteringFactor)) );
UIAccelerationValue accelZ = acceleration.z - ( (acceleration.z * kFilteringFactor) + (gravZ * (1.0 - kFilteringFactor)) );
accelX *= 9.81f;
accelY *= 9.81f;
accelZ *= 9.81f;
accelX = [self tendToZero:accelX];
accelY = [self tendToZero:accelY];
accelZ = [self tendToZero:accelZ];

UIAccelerationValue vector = sqrt(pow(accelX,2)+pow(accelY,2)+pow(accelZ, 2));
UIAccelerationValue acce = vector - prevVelocity;
UIAccelerationValue velocity = (((acce - prevAcce)/2) * (1/kAccelerometerFrequency)) + prevVelocity;

NSLog(@"X %g Y %g Z %g, Vector %g, Velocity %g",accelX,accelY,accelZ,vector,velocity);
于 2013-05-16T05:40:00.453 回答