linux - 交互式 Shell 脚本

Question

如何创建一个简单的 Shell 脚本，该脚本要求用户提供简单的输入，然后仅运行与预定义选项相关的命令，例如

IF "ON"
Backup Server
ELSEIF "OFF"
Delete Backups
ELSEIF "GREY"
Send Backups
ENDIF

Answer 1

您可以通过从用户那里获取输入，read并且可以使用case ... esac块来做不同的事情。

Read 将变量的名称作为它的参数，它将存储它的值

read foo

将从用户那里获取一个值并将其存储在$foo.

要提示用户输入，您需要使用 echo。

echo "What is your favourite color?"
read color

最后，大多数 shell 脚本都支持 case 运算符。采取的形式

case "value" in
    "CHOICE)
        # Do stuff
        ;;
esac

把它们放在一起：

echo "Which choice would you like? \c"
read choice

case "$choice" in

    ON)
        # Do Stuff
        ;;
    OFF)
        # Do different stuff
        ;;
    *)
        echo "$choice is not a valid choice"
        ;;
esac

Answer 2

#!/bin/bash

select choice in "ON" "OFF" "*"; do
case "$choice" in
    ON) echo "$choice"; # do something; 
    break;;
    OFF) echo "$choice"; # do something; 
    break;;
    *) echo "$choice other"; # do something; 
    break;;
esac
done

Answer 3

嗨，有一个简单的例子怎么做

while true; do
    read -p 'do you want to continue "y" or "n": ' yn

    case $yn in

        [Yy]* ) echo 'this program continue '; break;;

        [Nn]* ) exit;;

        * ) echo 'Please answer yes or no: ';;

    esac

done

while true; do
    read -p 'press "c" to quit this program: ' c

    case $c in

        [Cc]* ) exit;;

        * ) echo 'for quit this program press "c": ' ;;

    esac

done

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