我进行了很多搜索,但仍然无法将唯一 ID 传递给一个值,然后将该 ID 用于 PHP MySQL 查询以获取图书信息。
我目前正在将唯一 ID 传递给 Modal 并通过输入类型文本显示它。我只是很难弄清楚如何将 id 放入 php 变量中
这是我的 HTML/PHP 代码
echo '<a data-toggle="modal" data-id="' . $book_id .'" title="Add this item" class="open-AddBookDialog btn btn-primary" href="#addBookDialog">View Info</a>';?>
<!-- Modal -->
<div class="modal hide" id="addBookDialog">
<div class="modal-header">
<button class="close" data-dismiss="modal">×</button>
<h3>Book Info</h3>
</div>
<div class="modal-body">
<p>some content</p>
<?php
echo $test = '<input type="text" name="bookId" id="bookId"/>';
$book_info = get_book_info($book_id);
while($row1 = mysqli_fetch_array($book_info))
{
$email = $row['email'];
echo "<p><strong>Title: </strong>" . $row1['title'] . "</p>";
echo "<p><strong>Author: </strong>" . $row1['author'] . "</p>";
echo "<p><strong>Edition: </strong>" . $row1['edition'] . "</p>";
echo "<p><strong>ISBN: </strong>" . $row1['isbn'] . "</p>";
echo "<p><strong>Price: </strong>" . $row1['price'] . "</p>";
echo "<p><strong>Seller's Name: </strong>" . $row1['name'] . "</p>";
echo "<p><strong>Seller's E-mail: </strong><a href='mailto:$email'>$email</a></p>";
}?>
</div>
<div class="modal-footer">
<button class="btn" data-dismiss="modal" aria-hidden="true">Close</button>
</div>
</div>
这是我的jQuery
$(document).on("click", ".open-AddBookDialog", function () {
var myBookId = $(this).data('id');
$(".modal-body #bookId").val( myBookId );
});