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非常感谢大家的帮助，两个答案都很完美。我有一个 Java 实验室作业，我需要一些帮助。
任务是读取一个包含 28 个整数的 txt，然后将它们放入 2D 数组中。这是我所拥有的：

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class TextFileExample {
    public static void main(String[] args) {

        String fileName = "TemperatureData.txt";
        Scanner inputStream = null;
        System.out.println("The file " + fileName + "\ncontains the following lines:\n");
        try
        {
            inputStream = new Scanner(new File("C:\\Users\\username\\Documents\\TemperatureData.txt"));//The txt file is being read correctly.
            String line = inputStream.nextLine();
            String[] numbers = line.split("");
            int[][] temperatures = new int[4][7];
            for (int row = 0; row < 4; row++) {
                for (int column = 0; column < 7; column++) {
                    temperatures[row][column] = temperatures.parseInt(temperatures[row][column]);//Is this correct?
                }
            }
        }
        catch(FileNotFoundException e)
        {
            System.out.println("Error opening the file " + fileName);
            System.exit(0);
        }

        while (inputStream.hasNextLine())
        {
            String line = inputStream.nextLine();
            System.out.println(line);
        }
        inputStream.close();

    }
}

我需要一些关于将数据从 txt 文件中获取到数组中的帮助temperatures[4][7]。

然后打印出显示数据的温度数组。输出应如下所示：

Temperature Data

Week 1: 73 71 68 69 75 77 78

Week 2: 76 73 72 72 75 79 76

Week 3: 79 82 84 84 81 78 78

Week 4: 75 72 68 69 65 63 65

他不要求将 txt 文件作为输出。

txt文件是这样的：

73
71
68
69
75
77
78
76
73
72
72
75
79
76
79
82
84
84
81
78
78
75
72
68
69
65
63
65
4

2 回答 2

1 
temperatures[row][column] = temperatures.parseInt(temperatures[row][column]);

应该

temperatures[row][column] = Integer.parseInt(line);

另外，删除String[] numbers = line.split("");，因为它没有使用。

您需要重新排序一些东西才能使其正常工作。逻辑是：

Open file
if filenotfound, quit
loop through your arrays
    Parse the string in the file, put it in your array

现在你可以对数组做一些事情了。请注意，这不能优雅地处理文件不够长的情况。

String fileName = "TemperatureData.txt";
Scanner inputStream = null;
System.out.println("The file " + fileName + "\ncontains the following lines:\n");
try
{
  inputStream = new Scanner(new File("C:\\Users\\username\\Documents\\TemperatureData.txt"));//The txt file is being read correctly.
}
catch(FileNotFoundException e)
{
  System.out.println("Error opening the file " + fileName);
  System.exit(0);
}

for (int row = 0; row < 4; row++) {
  for (int column = 0; column < 7; column++) {
    String line = inputStream.nextLine();
    int[][] temperatures = new int[4][7];
    temperatures[row][column] = Integer.parseInt(line);
  }
}
inputStream.close();
于 2013-05-04T23:08:37.963 回答
0

这是一个解决方案：

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.InputMismatchException;
import java.util.Scanner;
import java.util.StringTokenizer;

public class TxtTo2DArray {
public static void main(String[] args) throws FileNotFoundException, IOException {

    String filename = ""; //Here you must write the path to the file f.exp "//folder//file.txt"

    try{
    FileReader readConnectionToFile = new FileReader(filename);
    BufferedReader reads = new BufferedReader(readConnectionToFile);
    Scanner scan = new Scanner(reads);

    int[][] temperatures = new int[4][7];
    int counter = 0;
    try{
        while(scan.hasNext() && counter < 5){
            for(int i = 0; i < 4; i++){
                counter = counter + 1;
                for(int m = 0; m < 7; m++){
                    temperatures[i][m] = scan.nextInt();
                }
            }
    }

            for(int i = 0; i < 4; i++){
            System.out.println("Temperature at week:" + (i + 1) + " is: " + temperatures[i][0] + ", " + temperatures[i][1] + ", " + temperatures[i][2] + ", " + temperatures[i][3] + ", " + temperatures[i][4] + ", " + temperatures[i][5] + ", " + temperatures[i][6]);

            }

    } catch(InputMismatchException e){
        System.out.println("Error converting number");
    }
    scan.close();
    reads.close();
    } catch (FileNotFoundException e){
        System.out.println("File not found" + filename);
    } catch (IOException e){
        System.out.println("IO-Error open/close of file" + filename);
    }

}     
}

使用您的文件给出了以下结果：

Temperature at week:1 is: 73, 71, 68, 69, 75, 77, 78
Temperature at week:2 is: 76, 73, 72, 72, 75, 79, 76
Temperature at week:3 is: 79, 82, 84, 84, 81, 78, 78
Temperature at week:4 is: 75, 72, 68, 69, 65, 63, 65
于 2013-05-04T23:37:41.433 回答