1

我有一个简单的登录页面，顶部是带有 if 和 elseif 语句的简单表单验证。我想将验证代码下方的 mysql select where 语句编写为（elseif）语句。如果邮箱和密码=数据库表记录上的邮箱和密码，那么它会将使用重定向到受保护的页面，如果邮箱或密码不存在或不匹配，最终（else）将显示错误数据库。

我真的不知道如何以正确的方式做到这一点，这是我的尝试，但它不起作用：

    <?php require_once("includes/connection.php"); ?>
<?php require_once("includes/functions.php"); ?>
<?php

$email = $_POST['Email'];
$hashed_password = md5($_POST['password']);

    if (isset($_POST['submit'])) { // Form has been submitted.

        if ($_POST['Email'] == "") {    
            $error = "Email address is required";
        }
        elseif (!(filter_var($_POST['Email'], FILTER_VALIDATE_EMAIL))) {
            $error = "Invalid email address";
        }
        elseif ($_POST['password'] == "") {
            $error = "Type in your password";
        }
        elseif (strlen($_POST['password']) < 8) {
            $error = "Minimum password length is 8";
        }
        elseif {
            $query = "SELECT id, email ";
            $query .= "FROM customers ";
            $query .= "WHERE email = '{$email}' ";
            $query .= "AND hashed_password = '{$hashed_password}' ";
            $query .= "LIMIT 1";
            $result_set = mysql_query($query);
            redirect_to("account.php");
        }
        else {
            echo "error";
        }

    }       
?>
    <!-- signup box -->
    <div id="box_sign">
        <div class="container">
            <div class="span12 box_wrapper">
                <div class="span12 box">
                    <div>
                        <div class="head">
                            <h4>Sign In</h4><br />
                             <div class="text-error">
                              <?php echo $error; ?><br />
                              <p class="text-success"><strong><?php echo $success; ?></strong></p>
                            </div>
                        </div>
                        <div class="form">
                            <form action="sign-in.php" method="POST">

                              <input type="text" id="Email" name="Email" placeholder="Email"/>

                              <input type="password" id="password" name="password" placeholder="Password"/>
                                    <div class="right">
                                        <a href="reset.html">Forgot password?</a>
                                    </div>
                              <input type="submit" name="submit" class="btn" value="Sign In"/>
                            </form>
                        </div>
                    </div>
                </div>
                <p class="already">Don't have an account? 
                    <a href="signin.html">Sign up</a></p>
            </div>
        </div>
    </div>
4

2 回答 2

2

redirect_to()不是预定义的 PHP 函数，它是自定义函数，可能您从其他地方选择了此代码，而您忘记了选择函数代码。应该是这个

function redirect_to($link) {
   header('Location: '.$link);
   exit;
}

也elseif {无效，没有条件它不会工作

于 2013-05-04T13:41:09.980 回答
0

改变：

elseif {
    $query = "SELECT id, email ";
    $query .= "FROM customers ";
    $query .= "WHERE email = '{$email}' ";
    $query .= "AND hashed_password = '{$hashed_password}' ";
    $query .= "LIMIT 1";
    $result_set = mysql_query($query);
    redirect_to("account.php");
}

至：

else {
    $query = "SELECT id, email ";
    $query .= "FROM customers ";
    $query .= "WHERE email = '{$email}' ";
    $query .= "AND hashed_password = '{$hashed_password}' ";
    $query .= "LIMIT 1";
    $result_set = mysql_query($query);
    if (mysql_num_rows()>0){
        Header("Location:account.php");
    }
    else {
        echo 'Password or email is wrong';
    }
}
于 2013-05-04T13:47:19.953 回答